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jhonyy9
 4 years ago
prove that every prim p>2 can be writing in the form of 2n+1 for n>0 ,n number natural,so p1=2n  p1  even,because p is odd.
so p>2  than p>=3
p is prim,p>2 so than p is even so p=2k+1,where k=1,2,3,...,n.
so p=2k+1  subtract 1 from both sides,than
p1=2k
2n=p1=2k so
2n=2k  divide both sides by 2
n=k
 so for every p prims there are n>=1,n natural ,
such that p=2n+1
 is this correct,right ?
jhonyy9
 4 years ago
prove that every prim p>2 can be writing in the form of 2n+1 for n>0 ,n number natural,so p1=2n  p1  even,because p is odd. so p>2  than p>=3 p is prim,p>2 so than p is even so p=2k+1,where k=1,2,3,...,n. so p=2k+1  subtract 1 from both sides,than p1=2k 2n=p1=2k so 2n=2k  divide both sides by 2 n=k  so for every p prims there are n>=1,n natural , such that p=2n+1  is this correct,right ?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0By division algorithm, every integer can be written in the form 2k or 2k+1.Primes are those which do not have ANY factors except 1 and itself.Thus, the form 2k is out of bounds for k>1. Thus, every prime >2 is of the form 2k+1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok but how to prove it this ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what ? can you write this here ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.01.Every int can be written as 2k or 2k+1. 2.The int 2k is divisible by 2.Thus it is not a prime for k>1 3.The conclusion follows.
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