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anonymous
 4 years ago
2013 + k is a perfect square . Find all the possible values of k.
anonymous
 4 years ago
2013 + k is a perfect square . Find all the possible values of k.

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Mr.Math
 4 years ago
Best ResponseYou've already chosen the best response.1You want to find all values of k such that \(2013+k=n^2 \implies k=n^22013\), which has infinitely many solutions over the integers. Thus there are infinitely many k such that \(2013+k\) is a perfect square.

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.0x^2 = 2013 + k > k = x^2 2013, for all integers x>0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and the smallest k is =2012

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0k=2013 is that possible?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(a+b+c)^2 = (2013 + k) is the original equation.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0are we looking for solution in R or C?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Mr. Math and dumbcow seem right..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0a,b,c are also integers?

EarthCitizen
 4 years ago
Best ResponseYou've already chosen the best response.0there should be only two values of k ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no,you are supposed to find all the possible values .

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0all possible values seem infinite..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.01 more condition : a^ + 2bc = 2012, b^2 + 2ca = 1,c^2 + 2ab = k.

Mr.Math
 4 years ago
Best ResponseYou've already chosen the best response.1Lol, Could your write the whole problem so we can help?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If a, b, c are integers such that a^ + 2bc = 2012, b^2 + 2ca = 1,c^2 + 2ab = k.Then,find all the possible values of k.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[ac \le0 \qquad a \le0 \quad or \quad c \le0\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is there any options?
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