Find the area of the equilateral triangle with sides 10 cm.. Ans is supposed to 43.3cm^2 (according to the answer sheet) but no workings are given :(

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Find the area of the equilateral triangle with sides 10 cm.. Ans is supposed to 43.3cm^2 (according to the answer sheet) but no workings are given :(

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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ar of equilateral triangle=root3/4a^2
First, divide in one of his heights the triangle into two triangles with a right angle (90, 60, 30 will be their angles). Then, you have 10 cm of hypothenuse, and 5 of base. You want to know the height. 10^2=height^2-5^2 75=height^2 sqrt(75)=height Then height*5/2 *2 (because you have 2 triangles) height*5=sqrt(75)*5=25*(sqrt(3))=43.3012~ cm2
|dw:1328412719708:dw| x^2+25=100 x=5(3)^1/2 Area=1/2*10*5(3)^1/2 =25(3)^1/2/2 =43.301cm^2

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