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anonymous
 4 years ago
g(x) = 2(x+1)^3 +8 (condition: x>1)
obtain an expression for g'(x) and use your answer to explain why g(x) has an inverse.
anonymous
 4 years ago
g(x) = 2(x+1)^3 +8 (condition: x>1) obtain an expression for g'(x) and use your answer to explain why g(x) has an inverse.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0chain rule g'(x)=h(j(x))'j'(x) h(x)=2x^3, j(x)=x+1, h'(x)=6x^2, j'(x)=1 6*(x+1)^2 6(x^2+2x+1) If x>1 then g'(x) is always >0, then it's strictly increasing. As g(x) is strictly increasing to all x>1, then it's inyective. As g(x) is never 0, then g^1(x) is defined to all x>1
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