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anonymous
 4 years ago
 let p and k prims,p>=2 and k>=2,
 let a and b natural numbers ,a>=1 and b>=1,
prove that for every n>=2 exist one a=(p1)/2 and b=(k1)/2 such that this equation n=a+b+1 is true .
for example :
2=(21)/2 +(21)/2 +1
2= 1/2 +1/2 +1
2=1+1
2=2
or 3=(31)/2 +(31)/2 +1
3=1+1+1
3=3
or
4=(51)/2 +(31)/2 +1
4=2+1+1
4=4
anonymous
 4 years ago
 let p and k prims,p>=2 and k>=2,  let a and b natural numbers ,a>=1 and b>=1, prove that for every n>=2 exist one a=(p1)/2 and b=(k1)/2 such that this equation n=a+b+1 is true . for example : 2=(21)/2 +(21)/2 +1 2= 1/2 +1/2 +1 2=1+1 2=2 or 3=(31)/2 +(31)/2 +1 3=1+1+1 3=3 or 4=(51)/2 +(31)/2 +1 4=2+1+1 4=4

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0n = (p1)/2 + (k1)/2 +1 = (p+k)/2. Thus, what the question is actually asking is to prove that are always an infinite number of primes>2 such that the sum of any two of them is even.But this is obviously true as any prime>2 is odd and the sum of two odd numbers is always even.
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