anonymous
  • anonymous
wat is meant by saying if spring is cutted in pieces then wat will be the relation before cutting spring
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
assume the dat spring ius cutted in equal halves
anonymous
  • anonymous
den wat we can predict abu dat halves?
wasiqss
  • wasiqss
sirf length change hogi cutting mai, spring constant remains same

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anonymous
  • anonymous
ok..
anonymous
  • anonymous
No wasqiss is wrong. If you cut a spring in two then spring constant doubles.
anonymous
  • anonymous
|dw:1328373587473:dw|
anonymous
  • anonymous
mera ans ni a rha isse ques. a spring constant of two springs are K1 and K2 such that one peice is double of the other. then the long peice will have a force constant of??
wasiqss
  • wasiqss
Since f=kx, then k=f/x. Now if you apply the same force to the half-length spring it only moves half as far. So if x is halved above, then k will double. Basically there are now half as many coils to take up the force via displacement.
anonymous
  • anonymous
well not getting ans dats y i post ques ans is 3/2K
anonymous
  • anonymous
(3/2)k
anonymous
  • anonymous
If you cut a spring of constant k into two springs of constants k1 and k2 and lengths l1 and l2 then 1/k=1/k1+ 1/k2. And k1/k2=l2/l1.solve these two equations to get the answer.
wasiqss
  • wasiqss
Let us look at a 10 coil spring as an example. Suppose we apply a force to the spring that compresses it 1 inch meaning that each coil is compressed 1/10 of an inch. If we then cut the spring in half, leaving 5 coils, and then compress it 1 inch, then each coil is compressed 2/10 or 1/5 of an inch. The general spring equation is F = -kx where F is the applied force, k is the spring constant and x is the distance the spring is compressed. So the force needed to compress a single coil by 2/10 of an inch is twice as large as to compress it 1/10 of an inch. Therefore the spring constant (k) of the 5-coil spring must be twice that of the 10-coil spring, because each individual coil of the 5-coil spring is compressed twice as far as each individual coil of the 10-coil spring for the same overall distance. So in general the spring constant of a spring is inversely proportional to the number of coils in the spring.
anonymous
  • anonymous
guys ans is (3/2)k and shankvee ur formula is rit but can u tell me is K dont changes if l increases plz ??
anonymous
  • anonymous
K does change if you cut it into two.I don't think i got your question properly....
anonymous
  • anonymous
ques. a spring constant of two springs are K1 and K2 such that one peice is double of the other. then the long peice will have a force constant of??
anonymous
  • anonymous
Since one piece is double the other k1/k2=1/2. 1/k=1/k1 +1/k2. So, k1=k2/2, 3/k2=1/k. k2=3k and k1=3/2 k. The longer peice is k1=3/2k
wasiqss
  • wasiqss
yaar heena ques toh sahi likha karo
anonymous
  • anonymous
sahi toh likha h..
wasiqss
  • wasiqss
shuru mai galat tha
anonymous
  • anonymous
kaha?? vo to mera doubt tha if u can see
wasiqss
  • wasiqss
ahhh ok dint read that fully
anonymous
  • anonymous
and shankvee how u get tat springs are arranged in parallel or series??
anonymous
  • anonymous
toh kisk galti ti... bolo bolo k meri ti
anonymous
  • anonymous
If two springs have same extension then they are in parallel.
wasiqss
  • wasiqss
ok baba
anonymous
  • anonymous
yea dat i know but couldnt get hint in this ques where dey are talking abu extension??
anonymous
  • anonymous
Like |dw:1328374653040:dw| Here if block moves by x then both springs are definitely stretched by x.
anonymous
  • anonymous
|dw:1328374593437:dw|
anonymous
  • anonymous
jst simply..............
anonymous
  • anonymous
k..
anonymous
  • anonymous
Now in series like |dw:1328374762687:dw| The two are strectched by different amounts
anonymous
  • anonymous
This question will actually be series like |dw:1328374871961:dw| In the bottom the resultant spring constant will become equal to the original spring constant (Same as the b) part in the previous question).
anonymous
  • anonymous

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