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anonymous
 4 years ago
I have a question..
anonymous
 4 years ago
I have a question..

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It is easy calculate angle of the arc and compute the area of circular part add then the area of triangle

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0cinar, this looks really similar to a question that you recently deleted. Please don't delete and repost questions. Thanks!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0notsobright, please show your work..

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0So are we to assume that the cow can go around the 2ft wall and continue eating grass? So effectively, the rope is 6 feet at that point?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0cow is very smart and green area is all grass..

Mr.Math
 4 years ago
Best ResponseYou've already chosen the best response.0So we have 20 ft of fences?

Mr.Math
 4 years ago
Best ResponseYou've already chosen the best response.0If so, then the maximum area needed is that of a circle with perimeter of 20 ft, that's radius of \(\large \frac{10}{\pi}\) and area \(\large \frac{100}{\pi} \text{ft}^2\).

barrycarter
 4 years ago
Best ResponseYou've already chosen the best response.1It looks like the cow can eat a halfcircle of grass with radius 8ft, and then another halfcircle of grass with radius 6ft. That's: 1/2*Pi*8*8 + 1/2*Pi*6*6 = 50 Pi =~ 157.08 square feet of grass

barrycarter
 4 years ago
Best ResponseYou've already chosen the best response.1Correction: the 6ft rope should centered at the west edge of the fence, not where the cow is.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0barrycarter is right, you got a medal (:
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