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cinar

  • 3 years ago

I have a question..

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  1. cinar
    • 3 years ago
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  2. NotSObright
    • 3 years ago
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    It is easy calculate angle of the arc and compute the area of circular part add then the area of triangle

  3. farmdawgnation
    • 3 years ago
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    cinar, this looks really similar to a question that you recently deleted. Please don't delete and repost questions. Thanks!

  4. cinar
    • 3 years ago
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    notsobright, please show your work..

  5. cinar
    • 3 years ago
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  6. Mertsj
    • 3 years ago
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    So are we to assume that the cow can go around the 2ft wall and continue eating grass? So effectively, the rope is 6 feet at that point?

  7. cinar
    • 3 years ago
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    cow is very smart and green area is all grass..

  8. Mr.Math
    • 3 years ago
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    So we have 20 ft of fences?

  9. Mr.Math
    • 3 years ago
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    If so, then the maximum area needed is that of a circle with perimeter of 20 ft, that's radius of \(\large \frac{10}{\pi}\) and area \(\large \frac{100}{\pi} \text{ft}^2\).

  10. barrycarter
    • 3 years ago
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    It looks like the cow can eat a half-circle of grass with radius 8ft, and then another half-circle of grass with radius 6ft. That's: 1/2*Pi*8*8 + 1/2*Pi*6*6 = 50 Pi =~ 157.08 square feet of grass

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  11. barrycarter
    • 3 years ago
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    Correction: the 6ft rope should centered at the west edge of the fence, not where the cow is.

  12. cinar
    • 3 years ago
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    barrycarter is right, you got a medal (:

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