## cinar 3 years ago I have a question..

1. cinar

2. NotSObright

It is easy calculate angle of the arc and compute the area of circular part add then the area of triangle

3. farmdawgnation

cinar, this looks really similar to a question that you recently deleted. Please don't delete and repost questions. Thanks!

4. cinar

5. cinar

6. Mertsj

So are we to assume that the cow can go around the 2ft wall and continue eating grass? So effectively, the rope is 6 feet at that point?

7. cinar

cow is very smart and green area is all grass..

8. Mr.Math

So we have 20 ft of fences?

9. Mr.Math

If so, then the maximum area needed is that of a circle with perimeter of 20 ft, that's radius of $$\large \frac{10}{\pi}$$ and area $$\large \frac{100}{\pi} \text{ft}^2$$.

10. barrycarter

It looks like the cow can eat a half-circle of grass with radius 8ft, and then another half-circle of grass with radius 6ft. That's: 1/2*Pi*8*8 + 1/2*Pi*6*6 = 50 Pi =~ 157.08 square feet of grass

11. barrycarter

Correction: the 6ft rope should centered at the west edge of the fence, not where the cow is.

12. cinar

barrycarter is right, you got a medal (: