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NotSObrightBest ResponseYou've already chosen the best response.0
It is easy calculate angle of the arc and compute the area of circular part add then the area of triangle
 2 years ago

farmdawgnationBest ResponseYou've already chosen the best response.0
cinar, this looks really similar to a question that you recently deleted. Please don't delete and repost questions. Thanks!
 2 years ago

cinarBest ResponseYou've already chosen the best response.0
notsobright, please show your work..
 2 years ago

MertsjBest ResponseYou've already chosen the best response.0
So are we to assume that the cow can go around the 2ft wall and continue eating grass? So effectively, the rope is 6 feet at that point?
 2 years ago

cinarBest ResponseYou've already chosen the best response.0
cow is very smart and green area is all grass..
 2 years ago

Mr.MathBest ResponseYou've already chosen the best response.0
So we have 20 ft of fences?
 2 years ago

Mr.MathBest ResponseYou've already chosen the best response.0
If so, then the maximum area needed is that of a circle with perimeter of 20 ft, that's radius of \(\large \frac{10}{\pi}\) and area \(\large \frac{100}{\pi} \text{ft}^2\).
 2 years ago

barrycarterBest ResponseYou've already chosen the best response.1
It looks like the cow can eat a halfcircle of grass with radius 8ft, and then another halfcircle of grass with radius 6ft. That's: 1/2*Pi*8*8 + 1/2*Pi*6*6 = 50 Pi =~ 157.08 square feet of grass
 2 years ago

barrycarterBest ResponseYou've already chosen the best response.1
Correction: the 6ft rope should centered at the west edge of the fence, not where the cow is.
 2 years ago

cinarBest ResponseYou've already chosen the best response.0
barrycarter is right, you got a medal (:
 2 years ago
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