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anonymous

  • 4 years ago

Thanks to all who answered my previous question but I have another: I need to prove DF and EB parallel. I was thinking that after I proved the two triangles congruent, I could just say corresponding angles are congruent, but I think that is wrong. how far off am I and how would you correct it? ( a picture will be provided)

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  1. anonymous
    • 4 years ago
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    |dw:1328376599870:dw| ABCD is a parraleogram

  2. aroub
    • 4 years ago
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    I think : First you say that< D and <B are alternate and then like what you said you prove the two triangles are congruent and then you prove that < D and <B are congruent by cpctc and because they are congruent DF & EB are parallel.

  3. jhonyy9
    • 4 years ago
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    DF and BE are angle bisectors and because we know that angle D = angle B so from this result that DF and BE are parallel

  4. aroub
    • 4 years ago
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    How did you know that they are angle bisectors ?

  5. jhonyy9
    • 4 years ago
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    so i have just supposed this so if are bisectors than ...

  6. anonymous
    • 4 years ago
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    no, no bisectors

  7. anonymous
    • 4 years ago
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    so...

  8. anonymous
    • 4 years ago
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    anyone...

  9. aroub
    • 4 years ago
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    What do you think of my answer ?

  10. anonymous
    • 4 years ago
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    I don't understand why <D and < B are alternate if they don't lie on the same tranversal

  11. aroub
    • 4 years ago
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    Change <D & <B to <1 & <2

  12. aroub
    • 4 years ago
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    You'll prove it by statements and reasons ?

  13. anonymous
    • 4 years ago
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    yeah

  14. aroub
    • 4 years ago
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    Good luck :)

  15. anonymous
    • 4 years ago
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    haha thanks

  16. aroub
    • 4 years ago
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    I think if you changed <B & <D to <1 and <2 it will work. Haha NP :D

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