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anonymous
 4 years ago
If the side opposite the 60degree angle in a 3060degree right triangle has a length of 10cm, what is the length of the hypotenuse and the length of the other leg?
anonymous
 4 years ago
If the side opposite the 60degree angle in a 3060degree right triangle has a length of 10cm, what is the length of the hypotenuse and the length of the other leg?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Hypotenuse = 10/sin60 base=10/tan60

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Is the hypotenuse side negative? That is what I am getting.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the length of one side not can being negativ never

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0When I divide 10 into sin60 negative comes up.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sin 60 equal how many ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no check it on your mathbooh or wikipedia

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0for the hypotenuse side= 11.5470054 base side= 5.77350269

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0does that seem right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0first week in trig, and i'm already lost! haha

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok but remember that the lenght of a side not can being never negativ

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yesir! but do my answers make sense?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can you make one draw  schem  for you can seeing it ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328379129214:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so sin 30 =1/2  suppose that i remember right,correct again sin 45 = (sqrt2)/2 sin 60 = (sqrt3)/2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sin 60 = BC / AC (sqrt3)/2 = 10/AC than AC=20/(sqrt3) = 20sqrt3/3 sin 30 = AB/AC 1/2 = AB/(20sqrt3/3) (20sqrt3)/3 =2AB AB=(20sqrt3)/6

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hope so much that is understandably good luck bye
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