anonymous
  • anonymous
If the side opposite the 60degree angle in a 30-60degree right triangle has a length of 10cm, what is the length of the hypotenuse and the length of the other leg?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
Hypotenuse = 10/sin60 base=10/tan60
anonymous
  • anonymous
Is the hypotenuse side negative? That is what I am getting.
jhonyy9
  • jhonyy9
the length of one side not can being negativ never

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More answers

anonymous
  • anonymous
When I divide 10 into sin60 negative comes up.
jhonyy9
  • jhonyy9
sin 60 equal how many ?
anonymous
  • anonymous
-0.304
jhonyy9
  • jhonyy9
no check it on your mathbooh or wikipedia
jhonyy9
  • jhonyy9
mathbook sorry
anonymous
  • anonymous
.866?
anonymous
  • anonymous
for the hypotenuse side= 11.5470054 base side= 5.77350269
anonymous
  • anonymous
does that seem right?
anonymous
  • anonymous
first week in trig, and i'm already lost! haha
jhonyy9
  • jhonyy9
ok but remember that the lenght of a side not can being never negativ
anonymous
  • anonymous
yesir! but do my answers make sense?
jhonyy9
  • jhonyy9
can you make one draw - schem - for you can seeing it ?
jhonyy9
  • jhonyy9
|dw:1328379129214:dw|
jhonyy9
  • jhonyy9
BC equal 10 cm
jhonyy9
  • jhonyy9
so sin 30 =1/2 --- suppose that i remember right,correct again sin 45 = (sqrt2)/2 sin 60 = (sqrt3)/2
jhonyy9
  • jhonyy9
sin 60 = BC / AC (sqrt3)/2 = 10/AC than AC=20/(sqrt3) = 20sqrt3/3 sin 30 = AB/AC 1/2 = AB/(20sqrt3/3) (20sqrt3)/3 =2AB AB=(20sqrt3)/6
jhonyy9
  • jhonyy9
hope so much that is understandably good luck bye

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