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anonymous

  • 4 years ago

If the side opposite the 60degree angle in a 30-60degree right triangle has a length of 10cm, what is the length of the hypotenuse and the length of the other leg?

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  1. anonymous
    • 4 years ago
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    Hypotenuse = 10/sin60 base=10/tan60

  2. anonymous
    • 4 years ago
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    Is the hypotenuse side negative? That is what I am getting.

  3. jhonyy9
    • 4 years ago
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    the length of one side not can being negativ never

  4. anonymous
    • 4 years ago
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    When I divide 10 into sin60 negative comes up.

  5. jhonyy9
    • 4 years ago
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    sin 60 equal how many ?

  6. anonymous
    • 4 years ago
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    -0.304

  7. jhonyy9
    • 4 years ago
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    no check it on your mathbooh or wikipedia

  8. jhonyy9
    • 4 years ago
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    mathbook sorry

  9. anonymous
    • 4 years ago
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    .866?

  10. anonymous
    • 4 years ago
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    for the hypotenuse side= 11.5470054 base side= 5.77350269

  11. anonymous
    • 4 years ago
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    does that seem right?

  12. anonymous
    • 4 years ago
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    first week in trig, and i'm already lost! haha

  13. jhonyy9
    • 4 years ago
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    ok but remember that the lenght of a side not can being never negativ

  14. anonymous
    • 4 years ago
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    yesir! but do my answers make sense?

  15. jhonyy9
    • 4 years ago
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    can you make one draw - schem - for you can seeing it ?

  16. jhonyy9
    • 4 years ago
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    |dw:1328379129214:dw|

  17. jhonyy9
    • 4 years ago
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    BC equal 10 cm

  18. jhonyy9
    • 4 years ago
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    so sin 30 =1/2 --- suppose that i remember right,correct again sin 45 = (sqrt2)/2 sin 60 = (sqrt3)/2

  19. jhonyy9
    • 4 years ago
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    sin 60 = BC / AC (sqrt3)/2 = 10/AC than AC=20/(sqrt3) = 20sqrt3/3 sin 30 = AB/AC 1/2 = AB/(20sqrt3/3) (20sqrt3)/3 =2AB AB=(20sqrt3)/6

  20. jhonyy9
    • 4 years ago
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    hope so much that is understandably good luck bye

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