let F(x)=arctan xthen the domain of f(x) is all real numbers and the range is (-pi/2, pi/2) true false ?

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let F(x)=arctan xthen the domain of f(x) is all real numbers and the range is (-pi/2, pi/2) true false ?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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no domain for arctan is any x so the answer is false
are you sure i think its true
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sorry for my drawing talent but you can see clearly that domain is any x, but range of function is from -pi/2 to pi/2...these two horizontal lines
True
Domain is all real nos
tdiaz I have a weird feeling that you don't trust me :D
arctan is inverse function to tan(x), so the domain and range are flipped for tan(x) , Domain is (-pi/2, pi/2). Range is All Real therefore for arctan: Domain is All Real, Range is (-pi/2, pi/2)
that's right

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