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anonymous
 4 years ago
let F(x)=arctan xthen the domain of f(x) is all real numbers and the range is (pi/2, pi/2)
true
false ?
anonymous
 4 years ago
let F(x)=arctan xthen the domain of f(x) is all real numbers and the range is (pi/2, pi/2) true false ?

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nenadmatematika
 4 years ago
Best ResponseYou've already chosen the best response.1no domain for arctan is any x so the answer is false

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0are you sure i think its true

nenadmatematika
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1328377657829:dw

nenadmatematika
 4 years ago
Best ResponseYou've already chosen the best response.1sorry for my drawing talent but you can see clearly that domain is any x, but range of function is from pi/2 to pi/2...these two horizontal lines

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Domain is all real nos

nenadmatematika
 4 years ago
Best ResponseYou've already chosen the best response.1tdiaz I have a weird feeling that you don't trust me :D

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.0arctan is inverse function to tan(x), so the domain and range are flipped for tan(x) , Domain is (pi/2, pi/2). Range is All Real therefore for arctan: Domain is All Real, Range is (pi/2, pi/2)
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