need explination: find equation of a circle with in standard form with a diameter tht has endpoints at 6,-2 and -4,4
Stacey Warren - Expert brainly.com
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so equation of the circle is (x-1)^2+(y-1)^2=136
The equation you have doesnt satisfy the points though.
I think this is the process:
First we find the length of the diameter, we just make a triangle from the two points|dw:1328380595002:dw|
Using the pythagorean thereom, we can find the length of the diameter which is root 136
But we know that the radius is half of that, which is root 136 /2.
Finding the centre of the diameter, as nena has done already, the centre of the circle is (1,1)
So plugging all this in, we get
(x-1)^2 + (y-1)^2 = 34
The 34 comes from r^2, which is root(136)/2 all squared
= 136/4 = 34