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anonymous
 4 years ago
given that f(x) =(∛x1)/(x1) then its limit as x approaches 1 is equal to?
a.0
b.1
c.1
d.does not exist
anonymous
 4 years ago
given that f(x) =(∛x1)/(x1) then its limit as x approaches 1 is equal to? a.0 b.1 c.1 d.does not exist

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is (x1) all under the cube root?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0No option seem correct

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0x1 not under the cube root

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0\[\text{ let } u=x^\frac{1}{3} ; x>1 => u>(1)^\frac{1}{3}=1\] so we have \[\lim_{u \rightarrow 1}\frac{u1}{u^31}=\lim_{u \rightarrow 1}\frac{u1}{(u1)(u^2+u+1)}\]

nenadmatematika
 4 years ago
Best ResponseYou've already chosen the best response.2solution is 1/3 if you wrote it correctly

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so if theres no answer i put E.

nenadmatematika
 4 years ago
Best ResponseYou've already chosen the best response.2I suggest you type it again more carefuly and post again...so I would be sure

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It's 0, look at myininaya's solution... \[\frac{11}{1^2+1+1}=\frac{0}{3}=0\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0hey rick that top part cancels with (x1) though

nenadmatematika
 4 years ago
Best ResponseYou've already chosen the best response.2Nenad is the champ :D

nenadmatematika
 4 years ago
Best ResponseYou've already chosen the best response.2hahaha...kidding

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0this one has a sqr (∛x1) the other 1 hast no cube root (x1) and i feel nenad is the champ XD + myiniaya XD

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow 1}\frac{\sqrt[3]{x1}}{x1}\] are you saying this is the problem?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that's what i asked him earlier..he said no

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0YES THATS the one thanks

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry rick im confused

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so what is my answer d or e? e for error

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow 1}\frac{\sqrt[3]{x1} \cdot (x1)^3}{(x1) \cdot (x1)^3}\] \[\lim_{x \rightarrow 1}\frac{(x1)}{(x1)(x1)^3}=\lim_{x \rightarrow 1}\frac{1}{(x1)^4}\] I get the limit does not exist

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0d is wrong to i got the result of my question i got 16/20 =90 ^^ thanks to all of u
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