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if you cant open the file, let me know please
The graph of the function f(x) is given above. Find f'(1/2).
f'(1/2) = 0
can you explain please
i dont see why
It is not 0
answer is not zero
Intercepts are not clear Slope is constant i.e f'(x) is constant
Yeah, it's not zero
Ans is (y-intercept/x-intrecept)
x and y
yes i know, but at which point
Sorry, you're right, it's not zero. What you have to do is find the slope of the line first. The slope of the line = the derivative.
thats what i was thinking too
we have to do more than find the slope dont we?
(8-4)/(1-.25) = 4/(3/4) = 16/3 If that's not it then I don't know what is..
no its not
you typed 16/3 ?
i think its 3/1 so 3
but its not
rise over run
I just looked over the graph, the lines don't match up the way I thought they did. This question is pretty whack.
Are you still trying to find the answer to it? I want to give it one last shot
yes i am lol
not the answer
3.125 Try that
If that isn't it, I quit
its not. thanks for trying to figure it out though.
the answer is 5. i figured it out.
What did you do? Keep guessing until you got it?
did rise over run
i did it wrong at first
it goes up by 5 and over 1
5/1 = 5
How'd you figure that out?
i have notes from class
Actually, that's a shortcut way to do it. I remember now that you're supposed to use the x and y intercepts to do it if it crosses both axes. The x intercept = .6 The y intercept = 3 So the slope is rise/run = y/x = 3/.6 = 5 I completely bombed this question.
at least you tried, thanks