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anonymous
 4 years ago
Challenge:
\[f(x)=\sum_{n=1}^{infinty}\sin(\frac{2x}{3^n})\sin(\frac{x}{3^n})\]
find f(x) (independent of x) also evaluate the sum of the solutions of the equations f(x)=0 lying in the interval (0,629).
anonymous
 4 years ago
Challenge: \[f(x)=\sum_{n=1}^{infinty}\sin(\frac{2x}{3^n})\sin(\frac{x}{3^n})\] find f(x) (independent of x) also evaluate the sum of the solutions of the equations f(x)=0 lying in the interval (0,629).

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I didn't make this up I have hundreds of such problems

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What book do you have for these?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It is more of uncomplied collection

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sin2x = 2cosx*sinx But it doesn't seem to work

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0We shall use transformation formula

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sinxsin2x=1/2 (cosxcos3x)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh yeah cosccosd, Sorry

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0NotSObright you're so bright! I think we have it now

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I know summation formula for cos of angles in AP not GP

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[f(x) = \cos \frac{x}{3^n}  \cos x, n \to \infty \implies \frac{x}{3^n} \to 0 \implies \cos0 \to 1 \] \[f(x) = 1\cos{x}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I would like to answer more of such problems

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah cant forget that 2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Look at the new thread
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