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anonymous

  • 4 years ago

One of the roots of equation 2000x^6 +100x^5 +10x^3 +x -2 =0 is of form \[\frac{m+\sqrt{n}}{r}\] where m is non zero integer n and r are relatively prime natural nos.FInd value of m+n+r

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  1. anonymous
    • 4 years ago
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    Don't Cheat

  2. anonymous
    • 4 years ago
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    Donot wolfram it

  3. anonymous
    • 4 years ago
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    I won't :-)

  4. anonymous
    • 4 years ago
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    \[\frac{m-\sqrt{n}}{r}\] must be root

  5. anonymous
    • 4 years ago
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    I got it to \[(100x^4 +10x^2+1)(20x^2-2 +x)=0\]

  6. anonymous
    • 4 years ago
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    Now I think we can solve it

  7. anonymous
    • 4 years ago
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    200 :P

  8. anonymous
    • 4 years ago
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    took me time to factorize :-/

  9. anonymous
    • 4 years ago
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    Yes, cinar is right I got 200 as well

  10. anonymous
    • 4 years ago
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    I love solving such questions, these are so fun. I hate school math

  11. anonymous
    • 4 years ago
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    \[(ax^2+bx+c)*(dx^4+ex^3+fx^2+gx+h)=\] =\[2000x^6+100x^3+x-2\]

  12. anonymous
    • 4 years ago
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    Hmm factorization that's all, take some terms common and then try to take some more that's it

  13. anonymous
    • 4 years ago
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    I like your way though

  14. anonymous
    • 4 years ago
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    wow then, you saw it huh..

  15. anonymous
    • 4 years ago
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    Did you use hit and trial. or some standard manipulatoin

  16. anonymous
    • 4 years ago
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    cinar's way is a standard way. mine is kind of hit and trial with inuition maybe

  17. anonymous
    • 4 years ago
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    Fact about polynomials is that any polynomial can be factorised into quadratic and linear factors but it is not always feasible

  18. anonymous
    • 4 years ago
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    Solivng a system of six equation doesnot seem promising also equatoins are not all linear

  19. anonymous
    • 4 years ago
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    hmm yeah. so what do you suggest what should we use?

  20. anonymous
    • 4 years ago
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    Cinar..we would find three sets of a,b,c But how to solve the system

  21. anonymous
    • 4 years ago
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    sorry guys, I have no time now, I can see it at night..

  22. anonymous
    • 4 years ago
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    Alright Meet me tommorrow 12:00 pm IST

  23. anonymous
    • 4 years ago
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    For more such problems Ishaan

  24. anonymous
    • 4 years ago
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    IST? Indian Standard Time? you from India?

  25. anonymous
    • 4 years ago
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    ya

  26. anonymous
    • 4 years ago
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    Yeah I like these but it's late here and I have a problem to finish. I have posted it on OpenStudy you can check it out http://openstudy.com/users/ishaan94#/updates/4f2d8011e4b0571e9cba7c3b

  27. anonymous
    • 4 years ago
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    Cool!

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