anonymous
  • anonymous
One of the roots of equation 2000x^6 +100x^5 +10x^3 +x -2 =0 is of form \[\frac{m+\sqrt{n}}{r}\] where m is non zero integer n and r are relatively prime natural nos.FInd value of m+n+r
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Don't Cheat
anonymous
  • anonymous
Donot wolfram it
anonymous
  • anonymous
I won't :-)

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More answers

anonymous
  • anonymous
\[\frac{m-\sqrt{n}}{r}\] must be root
anonymous
  • anonymous
I got it to \[(100x^4 +10x^2+1)(20x^2-2 +x)=0\]
anonymous
  • anonymous
Now I think we can solve it
anonymous
  • anonymous
200 :P
anonymous
  • anonymous
took me time to factorize :-/
anonymous
  • anonymous
Yes, cinar is right I got 200 as well
anonymous
  • anonymous
I love solving such questions, these are so fun. I hate school math
anonymous
  • anonymous
\[(ax^2+bx+c)*(dx^4+ex^3+fx^2+gx+h)=\] =\[2000x^6+100x^3+x-2\]
anonymous
  • anonymous
Hmm factorization that's all, take some terms common and then try to take some more that's it
anonymous
  • anonymous
I like your way though
anonymous
  • anonymous
wow then, you saw it huh..
anonymous
  • anonymous
Did you use hit and trial. or some standard manipulatoin
anonymous
  • anonymous
cinar's way is a standard way. mine is kind of hit and trial with inuition maybe
anonymous
  • anonymous
Fact about polynomials is that any polynomial can be factorised into quadratic and linear factors but it is not always feasible
anonymous
  • anonymous
Solivng a system of six equation doesnot seem promising also equatoins are not all linear
anonymous
  • anonymous
hmm yeah. so what do you suggest what should we use?
anonymous
  • anonymous
Cinar..we would find three sets of a,b,c But how to solve the system
anonymous
  • anonymous
sorry guys, I have no time now, I can see it at night..
anonymous
  • anonymous
Alright Meet me tommorrow 12:00 pm IST
anonymous
  • anonymous
For more such problems Ishaan
anonymous
  • anonymous
IST? Indian Standard Time? you from India?
anonymous
  • anonymous
ya
anonymous
  • anonymous
Yeah I like these but it's late here and I have a problem to finish. I have posted it on OpenStudy you can check it out http://openstudy.com/users/ishaan94#/updates/4f2d8011e4b0571e9cba7c3b
anonymous
  • anonymous
Cool!

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