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anonymous
 4 years ago
f(x) = 2x1 and h(x) = 3/x+1
what does (h*f)(2) = ??
anonymous
 4 years ago
f(x) = 2x1 and h(x) = 3/x+1 what does (h*f)(2) = ??

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Hero
 4 years ago
Best ResponseYou've already chosen the best response.2f(x) = 2x1 h(x) = 3/(x+1) f(2) = 2(2)  1 = 4  1 = 5 h(2) = 3/(2+1) = 3/3 = 1 (h*f)(2) = h(2)*f(2) = 1*5 = 5

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0f(2)=5 h(2)=1 f(2)*h(2)=5(1)=5

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Is that a valid way of writing f(2)*h(2) ?

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2* means times. It's valid for when you're using a computer or a calculator

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I meant (h*f) seems like multiplying "functions" rather than their values. Do you understand what I mean?

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2Yes, you can also multiply the functions, but that would take longer. It's easier to evaluate f(2) and h(2) then multiply that together. Either way, you would get the same answer.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hmmmm......i got the answer 3/4 ?? that is the answer in the book i am using.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0depends on whether you want \[f\times g(x)\] or \[f\circ g(x)\] they are different

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok that makes sense b/c the question was (h o f)(2)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0then \[h\circ f(2)=h(f(2))=h(5)=\frac{3}{5+1}=\frac{3}{4}\]
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