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anonymous

  • 4 years ago

f(x) = -2x-1 and h(x) = 3/x+1 what does (h*f)(2) = ??

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  1. Hero
    • 4 years ago
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    f(x) = -2x-1 h(x) = 3/(x+1) f(2) = -2(2) - 1 = -4 - 1 = -5 h(2) = 3/(2+1) = 3/3 = 1 (h*f)(2) = h(2)*f(2) = 1*-5 = -5

  2. Mertsj
    • 4 years ago
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    f(2)=-5 h(2)=1 f(2)*h(2)=-5(1)=-5

  3. anonymous
    • 4 years ago
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    Is that a valid way of writing f(2)*h(2) ?

  4. Hero
    • 4 years ago
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    * means times. It's valid for when you're using a computer or a calculator

  5. anonymous
    • 4 years ago
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    I meant (h*f) seems like multiplying "functions" rather than their values. Do you understand what I mean?

  6. Hero
    • 4 years ago
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    Yes, you can also multiply the functions, but that would take longer. It's easier to evaluate f(2) and h(2) then multiply that together. Either way, you would get the same answer.

  7. anonymous
    • 4 years ago
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    Thank you

  8. anonymous
    • 4 years ago
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    hmmmm......i got the answer -3/4 ?? that is the answer in the book i am using.

  9. anonymous
    • 4 years ago
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    depends on whether you want \[f\times g(x)\] or \[f\circ g(x)\] they are different

  10. anonymous
    • 4 years ago
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    ok that makes sense b/c the question was (h o f)(2)

  11. anonymous
    • 4 years ago
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    then \[h\circ f(2)=h(f(2))=h(-5)=\frac{3}{-5+1}=-\frac{3}{4}\]

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