Why is 13 and -5 the wrong answer?

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Why is 13 and -5 the wrong answer?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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ill type it out if you cant see it
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where did you get the 13 from?
take the derivative, replace x by 1 and you should get 10 if i am not mistaken
For the function f(x) = 5x^2+3, find the equation of the tangent line to the graph of f at x=1. If the equation of the tangent line is written as: y=mx+b, what are m and b? m= b=
find f(1) to establish the point and find f'(1) to establish a slope
then y = mx + b y = f'(1)x -f'(1)+f(1)
i got 13 by getting 10(1)+3
5(1)+3 = 8
5(1^2) not= 10
..... youre talking the derivative tho lol
derivative of 5x^2+3 is 10x 10(1) = 10
i am going to guess that the mistake was in taking the derivative and getting \[y'=10x+3\] instead of the correct \[y'=10x\] just a guess
y = 10x -10+8 y = 10x -2
what amistre said
yeah my mistake was that i kept the 3 after taking the derivative
\[D_x[5x^2+3]=Dx[5x^2]+Dx[3]=10x + 0\]
thanks

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