## anonymous 4 years ago Medals 4 grabs because I realize that I keep asking the same questions,so sorry...but "Find 3f(a-4)-2h(a) if f(x)=x^2 +3x and h(x)=2x^2-3x+5"

1. anonymous

lets take three steps 1) first find $3f(a-4)$ 2) then find $2h(x)$ 3) then subtract

2. anonymous

$f(x)=x^2+3x$ $2f(a-4)=2\left( (a-4)^2+3(a-4)\right)$ $=2\left( (a-4)(a-4)+3a-12\right)$ $2\left(a^2-8a+16+3a-12\right)$ $2\left(a^2-5a+4\right)$ $2a^2-10a+8$

3. anonymous

that was the hard part. easy part is $2h(a)=2(2a^2-3a+5)$ $=4a^2-6a+10$

4. anonymous

Its 3f...

5. anonymous

ok no problem

6. anonymous

$3\left(a^2-5a+4\right)$ $3a^2-15a+12$

7. anonymous

$2a^2-15a+12-(4a^2-6a+10)$