anonymous
  • anonymous
Medals 4 grabs because I realize that I keep asking the same questions,so sorry...but "Find 3f(a-4)-2h(a) if f(x)=x^2 +3x and h(x)=2x^2-3x+5"
Mathematics
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anonymous
  • anonymous
Medals 4 grabs because I realize that I keep asking the same questions,so sorry...but "Find 3f(a-4)-2h(a) if f(x)=x^2 +3x and h(x)=2x^2-3x+5"
Mathematics
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
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anonymous
  • anonymous
lets take three steps 1) first find \[3f(a-4)\] 2) then find \[2h(x)\] 3) then subtract
anonymous
  • anonymous
\[f(x)=x^2+3x\] \[2f(a-4)=2\left( (a-4)^2+3(a-4)\right)\] \[=2\left( (a-4)(a-4)+3a-12\right)\] \[2\left(a^2-8a+16+3a-12\right)\] \[2\left(a^2-5a+4\right)\] \[2a^2-10a+8\]
anonymous
  • anonymous
that was the hard part. easy part is \[2h(a)=2(2a^2-3a+5)\] \[=4a^2-6a+10\]

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anonymous
  • anonymous
Its 3f...
anonymous
  • anonymous
ok no problem
anonymous
  • anonymous
\[3\left(a^2-5a+4\right)\] \[3a^2-15a+12\]
anonymous
  • anonymous
\[2a^2-15a+12-(4a^2-6a+10)\]

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