anonymous
  • anonymous
From a standard desk of 52 card, 5 card are draw.What are the odds of each even occurring? a) 5 aces b) 5 face cards
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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ash2326
  • ash2326
a) 5 aces , there are 4 aces in a deck so probability of getting 5 aces is zero b) king queen and jack are face cards so total face cards= 12 no. of ways 5 face cards can be drawn= 12C5 no. of ways 5 cards can be drawn= 52C5 so probability of drawing 5 face cards= 12C5/ 52C5
anonymous
  • anonymous
tk,
ash2326
  • ash2326
welcome nancy did you understand

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anonymous
  • anonymous
I will give u a medal
ash2326
  • ash2326
I didn't ask for that, I asked if you understand:)
anonymous
  • anonymous
yes
anonymous
  • anonymous
actually it asks for odds, not probability, although the method of finding it is the same
anonymous
  • anonymous
take the number of ways to get five face cards, divide by the number of ways not got to get five face cards
anonymous
  • anonymous
number of ways to get 5 face cards is \[12\times 11\times 10\times 9\times 8=95040\] number of ways not to get five face cards is \[\dbinom{52}{5}-95040=2503920\]and so ODDS in favor of getting 5 face cards is \[95040:2503920\] or \[396:10433\]
anonymous
  • anonymous
I have a question ash
anonymous
  • anonymous
face have total 12 cards?
ash2326
  • ash2326
King, queen and jack are face cards, so there are 3 in each suit so total 12
anonymous
  • anonymous
I'm confuse
ash2326
  • ash2326
Nancy In a deck of 52 cards, there are 4 suits each suit has = 1 queen, 1 king and 1 jack= 3 face cards so in 4 suits we'll have 12 cards

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