From a standard desk of 52 card, 5 card are draw.What are the odds of each even occurring? a) 5 aces b) 5 face cards

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From a standard desk of 52 card, 5 card are draw.What are the odds of each even occurring? a) 5 aces b) 5 face cards

Mathematics
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a) 5 aces , there are 4 aces in a deck so probability of getting 5 aces is zero b) king queen and jack are face cards so total face cards= 12 no. of ways 5 face cards can be drawn= 12C5 no. of ways 5 cards can be drawn= 52C5 so probability of drawing 5 face cards= 12C5/ 52C5
tk,
welcome nancy did you understand

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I will give u a medal
I didn't ask for that, I asked if you understand:)
yes
actually it asks for odds, not probability, although the method of finding it is the same
take the number of ways to get five face cards, divide by the number of ways not got to get five face cards
number of ways to get 5 face cards is \[12\times 11\times 10\times 9\times 8=95040\] number of ways not to get five face cards is \[\dbinom{52}{5}-95040=2503920\]and so ODDS in favor of getting 5 face cards is \[95040:2503920\] or \[396:10433\]
I have a question ash
face have total 12 cards?
King, queen and jack are face cards, so there are 3 in each suit so total 12
I'm confuse
Nancy In a deck of 52 cards, there are 4 suits each suit has = 1 queen, 1 king and 1 jack= 3 face cards so in 4 suits we'll have 12 cards

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