anonymous
  • anonymous
This what I have so far...
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
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anonymous
  • anonymous
f'(x)=4x x=2 f'(2)=4(2)=8 which is m x=2 f(2)=2(2)^2+3=11 which is y (8,11) y-11=8(x-2) y=8x-5 what do i do next to find y1 and y2?
anonymous
  • anonymous
you need the equation for the line tangent to the graph. did you find that?

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anonymous
  • anonymous
huh?
anonymous
  • anonymous
you found it right?
anonymous
  • anonymous
the tangent line at (2,11) is \[y=8x-5 \]
anonymous
  • anonymous
so if you want the y value at some other point, replace x by the x value given
anonymous
  • anonymous
16-5=11
anonymous
  • anonymous
yes, and you knew that one to begin with right?
anonymous
  • anonymous
yes
anonymous
  • anonymous
since that is the point you used in the first place to find the line now replace x by -1 to find another point on the line
anonymous
  • anonymous
-8-5=-13
anonymous
  • anonymous
i guess. was the other x value -1?
anonymous
  • anonymous
yes
anonymous
  • anonymous
if so then you are right.

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