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Is your second equation right?
Ok just making sure so you can actually solve he second equation for x
from 2nd equation x = 66 plug this into first 8(66) - 30 = y y = 498 x=66,y=498
\[7x-8x=-66\] \[-1x=-66 => x=66\]
lol cwrw already got it
That is what I came up with to but the test answer was different
Maybe it was a type-o i bet
that one x is suppose to be a y
i wonder if we pretend it was a y if we could find the solution it was looking for
maybe \[7x=8y-66\] or \[7y=8x-66\]
The answer was (3,-6)
deanmary, you probably typed the equation wrong.
He said it was right. It might have been a type-o on the test. That is always possible. You should totally tell your teacher deanmary so you don't get penalized for it.