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tux
 4 years ago
Decide convergence/divergence
from n=1 to infinity
(2^n+1)/(3^n1)
tux
 4 years ago
Decide convergence/divergence from n=1 to infinity (2^n+1)/(3^n1)

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satellite73
 4 years ago
Best ResponseYou've already chosen the best response.0converges for sure, and in fact i think the sum is not even 5

satellite73
 4 years ago
Best ResponseYou've already chosen the best response.0ignore the irrelavent 1 and +1 and use the root test, get it right away

tux
 4 years ago
Best ResponseYou've already chosen the best response.0It is hard to calculate using root test

satellite73
 4 years ago
Best ResponseYou've already chosen the best response.0not when the index is in the exponent, then it is easy

satellite73
 4 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt[n]{2^n}=2\]!

tux
 4 years ago
Best ResponseYou've already chosen the best response.0Still have no idea how to do

Zarkon
 4 years ago
Best ResponseYou've already chosen the best response.1if you want...you can use the comparison test

Zarkon
 4 years ago
Best ResponseYou've already chosen the best response.1sure...use the limit comparison test then.
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