## tux Group Title Decide convergence/divergence from n=1 to infinity (2^n+1)/(3^n-1) 2 years ago 2 years ago

1. satellite73 Group Title

converges for sure, and in fact i think the sum is not even 5

2. satellite73 Group Title

ignore the irrelavent -1 and +1 and use the root test, get it right away

3. tux Group Title

It is hard to calculate using root test

4. satellite73 Group Title

not when the index is in the exponent, then it is easy

5. satellite73 Group Title

$\sqrt[n]{2^n}=2$!

6. tux Group Title

What to do with +1 and -1?

7. tux Group Title

Still have no idea how to do

8. Zarkon Group Title

if you want...you can use the comparison test

9. tux Group Title

Compare with (2/3)^n?

10. Zarkon Group Title

sure...use the limit comparison test then.