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  • tux

Decide convergence/divergence from n=1 to infinity (2^n+1)/(3^n-1)

Mathematics
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converges for sure, and in fact i think the sum is not even 5
ignore the irrelavent -1 and +1 and use the root test, get it right away
  • tux
It is hard to calculate using root test

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Other answers:

not when the index is in the exponent, then it is easy
\[\sqrt[n]{2^n}=2\]!
  • tux
What to do with +1 and -1?
  • tux
Still have no idea how to do
if you want...you can use the comparison test
  • tux
Compare with (2/3)^n?
sure...use the limit comparison test then.

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