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tux

Decide convergence/divergence from n=1 to infinity (2^n+1)/(3^n-1)

  • 2 years ago
  • 2 years ago

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  1. satellite73
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    converges for sure, and in fact i think the sum is not even 5

    • 2 years ago
  2. satellite73
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    ignore the irrelavent -1 and +1 and use the root test, get it right away

    • 2 years ago
  3. tux
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    It is hard to calculate using root test

    • 2 years ago
  4. satellite73
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    not when the index is in the exponent, then it is easy

    • 2 years ago
  5. satellite73
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    \[\sqrt[n]{2^n}=2\]!

    • 2 years ago
  6. tux
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    What to do with +1 and -1?

    • 2 years ago
  7. tux
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    Still have no idea how to do

    • 2 years ago
  8. Zarkon
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    if you want...you can use the comparison test

    • 2 years ago
  9. tux
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    Compare with (2/3)^n?

    • 2 years ago
  10. Zarkon
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    sure...use the limit comparison test then.

    • 2 years ago
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