evaluate the six trigonometric functions of the angle (see below for picture)

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

evaluate the six trigonometric functions of the angle (see below for picture)

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

the point is (4, -3) see the picture above
im just confused because the arrow goes all the way around so i dont know how to find answers

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

|dw:1328392741044:dw|
is that all i have to do
\[\sin(\theta)=\frac{opp}{hyp}=\frac{-3}{5}\]
and do i list negatives in the answers
oh wait
adj=4 opp=-3 hyp=5
i forgot thats not the angle. here is a new picture
feta is on the outside its the big one going around
??????
I'm confused Do you want to find theta or do you want us to evaluate theta using the 6 trig ratios?
Do the operation myinaya suggested, then add 360 to get the angle that is there
evalute using ratios. but im confused because the theta is on the outside and not the inside
let me look at your pic again one sec
ok look at the second one
ok
|dw:1328393266943:dw|
\[\sin(360^o-\theta^o)=\frac{opp}{hyp}=\frac{-3}{5}\] \[\sin(360)\cos(\theta)-\sin(\theta) \cos(360)=\frac{-3}{5}\]
\[(0) \cos(\theta)-\sin(\theta)(1)=\frac{-3}{5}\]
\[\sin(\theta)=\frac{3}{5}\]
Does that make since?
sense*?
no sry i dont get what u just said
which part?
There are 360 degrees in circle we have theta already making up part of that 360 degrees 360-theta is left to make a full rotation
Recall your sum and difference formulas
ok but how do i solve for sin cos tan etc if its on the outside
you will need those here
I just did sin(theta) for you
\[\cos(360-\theta)=\frac{4}{5}\] \[\cos(360)\cos(\theta)+\sin(360 )\sin(\theta)=\frac{4}{5}\]
\[1\cos(\theta)+0 \sin(\theta)=\frac{4}{5} => \cos(\theta)=\frac{4}{5}\]
so is it the same as being on teh inside
well sin(theta) does not equal sin(360-theta) but cos(theta) equals cos(360-theta) so it is not the same
it is not the same because it is not always true and i showed this by showing sin(theta) does not equal sin(360-theta)
but when i do it using theta on teh inside i get the same answers (sin is -3/5, cos is 4/5, tan is -3/4, etc
no sin(theta)=3/5 sin(360-theta)=-3/5 3/5 does not equal -3/5
ohh ok....thanks!!!
can i ask you another question
its kinda silly...but how do u simplify down (-4/\[\sqrt{52}\])
what is 13*4
\[\sqrt{52}=\sqrt{4} \sqrt{13}=2 \sqrt{13}\]
see pic above...i got it down to there but then stuck
\[\frac{-4}{2 \sqrt{13}}=\frac{-2}{\sqrt{13}}=\frac{-2 \sqrt{13}}{13}\]

Not the answer you are looking for?

Search for more explanations.

Ask your own question