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anonymous
 4 years ago
give the most general solutions to equations
2sinxcosxsin(2x)cos(2x)=0
A. simplify the first expression using double angle identity for sine.
B. factor the left side of equatioin
C. solve the factored equation
anonymous
 4 years ago
give the most general solutions to equations 2sinxcosxsin(2x)cos(2x)=0 A. simplify the first expression using double angle identity for sine. B. factor the left side of equatioin C. solve the factored equation

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i dont know how to simplify it, factor ir nor solve

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.22sinxcosx = sin(2x) 2sinxcosxsin(2x)cos(2x)=0 sin(2x)sin(2x)cos(2x)=0 now factor out sin(2x) sin(2x)[1  cos(2x)] = 0 sin(2x) = 0..since sin(0) = 0.. 2x = 0 x = 0 1 cos(2x) = 0 1 = cos(2x)...since cos(0) =1....2x = 0 x = 0

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0\[2\sin x \cos x2\sin x \cos x(12\sin ^2x)=0\] \[2\sin x \cos x[1(12\sin ^2x)]=0\] \[2\sin x \cos x(2\sin^2x)=0\] \[2\sin x=0, \cos x=0,,2\sin ^2x=0\]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0how do you solve for the second equation you have listed?
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