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anonymous
 4 years ago
2) evaluate each of the following in each case, and explain
a. cos^1(cos(pi/6)
part1: what is the value of cos(pi/6)
part2; to solve the problem cos^1(cos(pi/6))find the angle in interval [0,pi] whose cosine is sqrt3/2.
b. sin(tan^1(4/3))
part1: find the measure of the hypotenuse of this triangle.
part2: angle (theta) is the angle whose tan is 4/3. find the sine of angle (theta)
c. tan^1(cos(pi/2))
part1: what is the value of cos(pi/2)
part2: to solve tan^1(cos(pi/2)) find the angle in the interval [pi/2, pi/2] whose tangent equals 0.
anonymous
 4 years ago
2) evaluate each of the following in each case, and explain a. cos^1(cos(pi/6) part1: what is the value of cos(pi/6) part2; to solve the problem cos^1(cos(pi/6))find the angle in interval [0,pi] whose cosine is sqrt3/2. b. sin(tan^1(4/3)) part1: find the measure of the hypotenuse of this triangle. part2: angle (theta) is the angle whose tan is 4/3. find the sine of angle (theta) c. tan^1(cos(pi/2)) part1: what is the value of cos(pi/2) part2: to solve tan^1(cos(pi/2)) find the angle in the interval [pi/2, pi/2] whose tangent equals 0.

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Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0\[\cos (\frac{\pi}{6})=\frac{\sqrt{3}}{2}\]

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0The desired angle is \[\frac{\pi}{6}\]
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