## anonymous 4 years ago What is the inverse of the following equation x^2 +4 when x >0 is one to one ?

1. anonymous

The equation can be written as y = x^2 +4 the inverse is x = y^2 +4

2. Mertsj

$x=y^2+4$ $x-4=y^2$ $y=+\sqrt{x-4}$