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anonymous
 4 years ago
How do you find the nonpermissable replacement for the variable in this expression?
3x/3x+2
:( I'm so confused.
anonymous
 4 years ago
How do you find the nonpermissable replacement for the variable in this expression? 3x/3x+2 :( I'm so confused.

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Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2That would be the values of x that cause the fraction to be undefined. So we look for the values of x that make the denominator 0 and those are the nonpermissable replacements.

RagingSquirrel
 4 years ago
Best ResponseYou've already chosen the best response.0Welcome to openstudy!

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2\[3x+2=0\] \[x=\frac{2}{3}\]

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2So that would cause the denominator to be 0 and so it is not permitted as a replacement.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thank you very much :) I think I understand, but how do you figure out if they are equal to 0?

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2You set it equal to 0 so you can find what value cannot replace x.

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2Think of it this way. It is illegal to have a denominator of 0. So if the denominator is x, then it is illegal for x to be 0. If the denominator is x2 then it is illegal for x to be 2 If the denominator is x+3, then it is illegal for x to be 3 And so on... And you can find these numbers by writing (denominator) = 0 and solving. Then you will find the illegal numbers.
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