anonymous 4 years ago A particular form of electromagnetic radiation has a frequency of 5.42x10^15 Hz. What is the wavelength is nanometers? meters?

1. anonymous

We are dealing with electromagnetic (EM) radiation. Therefore, we know that in a vacuum, this EM wave (like any other EM wave) propagates a speed of 3 x 10^8 m/s. This is a property of EM radiation. $v = c = 3\times10^{8} m/s$ We are given the frequency of this EM wave: $f = 5.42\times10^{15} s ^{-1}$ Applying the formula $v = f \lambda$ we get $\lambda = v / f = c/f$$\lambda = (3 \times 10^{8} m/s)/(5.42 \times 10^{15} s^{-1}) = 5.54 \times 10^{-8}m$ Answer: 5.54 x 10^-8 m OR 55.4 nm

2. anonymous

okay, so how do i know figure out: what is the energy in joules of one quantum of this radiation?

3. anonymous

Energy is a different matter altogether. In order to find the energy of a quantum of EM radiation (i.e. a photon), you need to use another formula: $E = hf$ We are given that $f = 5.42\times10^{15}s ^{-1}$and $h = 6.63\times10^{-34} Js$(this is Planck's constant). Therefore, $E = (6.63\times10^{-34} Js)(5.42\times10^{15} s ^{-1}) = 3.59\times10^{-18} J$ Answer: 3.59 x 10^-18 J

4. anonymous

Similarly, you could use the wavelength of the EM radiation since $c = f \lambda$and so$E = hf = hc/\lambda$This would give you the same answer.