anonymous
  • anonymous
the functions f and g are given f=sqrt(x) and g = 6-x. Let R be the region bounded by the x-axis and the graphs of f and g. Find the area of R
Mathematics
jamiebookeater
  • jamiebookeater
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
can someone help
TuringTest
  • TuringTest
first step is to get an idea of the shape of the area:|dw:1329269119785:dw|it looks like we will have to do two separate integrals, because we can see that before the line x=xo we have the area as g-f, and after given by f-g. xo occurs when the functions intersect, so we can find it by solving\[f(x)=g(x)\]for x. our integral to find R will then be\[R=\int_{0}^{x_o}g-fdx+\int_{x_o}^{6}f-gdx\]
anonymous
  • anonymous
i found the intersection point between the two curve and its (4,2) so i integrated from 0 to 4 and did f - g why is that wrong?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

TuringTest
  • TuringTest
whoa sorry, misread just\[R=\int_{0}^{x_o}fdx+\int_{x_o}^{6}gdx\]
anonymous
  • anonymous
i get what you are saying their but i am a little confuse to how to know what integral to set up
anonymous
  • anonymous
btw thanks for the help
TuringTest
  • TuringTest
you found that the intersection point is at x=4|dw:1329269909705:dw|the first area is under f so it is\[R_1=\int_{0}^{4}fdx\]the second area is under g so it is\[R_2=\int_{4}^{6}gdx\]the total area is then\[R=R_1+R_2=\int_{0}^{4}fdx+\int_{4}^{6}gdx\]
TuringTest
  • TuringTest
|dw:1329270195071:dw|
anonymous
  • anonymous
I guess its wrong to why is it wrong to integrate for 0 to 6 of f - g...your pic is very good i get that...but i dont get why you can just integrate from 0 to 6
TuringTest
  • TuringTest
g>f for 0
TuringTest
  • TuringTest
\[\int_{0}^{4}fdx\]is this area:|dw:1329270801204:dw|
TuringTest
  • TuringTest
\[\int_{4}^{6}gdx\]would be this|dw:1329270875759:dw|
TuringTest
  • TuringTest
\[\int_{0}^{4}g-fdx\]would be this|dw:1329270925750:dw|it is important to think of the shape of each area...
anonymous
  • anonymous
Ok great explanations that you!!!
TuringTest
  • TuringTest
welcome :D
anonymous
  • anonymous
I will definately be asking more questions ....hope you can help me...lol i am sure you can
TuringTest
  • TuringTest
hope so :)
anonymous
  • anonymous
let me find some more

Looking for something else?

Not the answer you are looking for? Search for more explanations.