A chord of a circle of radius 10cm subtends a right angle the center.Find the area of minor sector.

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A chord of a circle of radius 10cm subtends a right angle the center.Find the area of minor sector.

Mathematics
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Ok. Now lets think. We have 1/4 of the entire circle. The entire circle has area 100 pi.
so 1/4 of the circle is 25 pi
The triangle is an isosceles right triangle and the legs are the base and height. So the area of the triangle is 1/2 (10)(10) or 50
If we subtract the 50 from 1/4 of the circle we should have the desired part.
25pi-50=???
Looking at the diagram the Mertsj drew, we can easily find the area of the minor sector: A(sector) = [(central angle) / (360 degrees)] x A(circle) The central angle is a right angle and measures 90 degrees. A(sector) = [(90 degrees) / (360 degrees)] x [(pi) x (10 cm)^2] = (1/4) x (100 cm^2)(pi) = 25pi cm^2 Answer: 25pi cm^2
pi = 3.14159...
I see physmath wants to help you now. Good Bye
And we are looking for the area of the minor sector NOT the area of the circular segment. So the answer is simply 25pi cm^2.
its okay bye thnx anyway !!!!
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No problem :)
I don't know if you are still there or not. But physmath is incorrect. The minor segment is the region bounded by the chord and the minor arc intercepted by the chord.
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Mertsj, the question asks for the minor SECTOR and NOT the SEGMENT. What you are referring to is called the CIRCULAR SEGMENT but the question is not asking for this. If you disagree, simply search up the definition of the two terms.

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