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anonymous
 4 years ago
What is the area under the curves of y=3, 2y=5(x)^1/2 and 2y+x=6
anonymous
 4 years ago
What is the area under the curves of y=3, 2y=5(x)^1/2 and 2y+x=6

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is there a picture attached?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ah well it's just that graphing this is going to be a pain.. So let's see what we can do

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no but I can attach one

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if u can, please do so haha

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0omg lol more of these webworks... i'm so sick of them haha

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0nah it's fine.. actually give the wolframalpha link, they also list the intercepts. it's easier.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=Graph+y%3D3%2C+2y%3D5x^%281%2F2%29%2C+2y%2Bx%3D6

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0all right great thanks. Here we go..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So here I'm going to split the graph in two at the point where x+2y = 6 and 2y = 5sqrt(x) intersect

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0That's the upper limit of our first integral

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sorry my browser's having trouble, anyway the upper intersect was 1. Now the lower intersect, which occurs when y =3 and 2y+x=6 intersect.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.06+x=6, x = 0. So the first half of that area is: Integral (upper curve  lower curve, 0,1)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how did you get one I got 1.36 doesnt it turn into a quadratic

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0x+5sqrt(x) = 6? Well I mean take a look, what number plus 5 times it's square root is 6?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay i get it i never thought of it like that

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Keep in mind, we're still calculating the first half. So now, the upper curve minus the lower curve (well they're lines, but whatever) is: 3  (6x)/2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So so far, the first half of our area is: Integral (3  (6x)/2, 0,1)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Now let's find the 2nd half: This time the lower limit is 1, because we are starting at one, and the upper limit is the intersection of y=3 and y = 5/2sqrt(x)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(5/2)*sqrt(x) = 3 sqrt(x) = 6/5 => x = 36/25

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So 2nd integral is again, upper curve minus the lower curve from 1 to 36/25, or Integral (3  (5/2)*sqrt(x), 1, 36/25)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Calculate each integral and then add them to get 107/300 (lol I cheated, used wolf to compute)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yea that looks right.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0k i will try it and tell you if it works

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it works thanks sooooo much you have no idea
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