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anonymous
 4 years ago
Solve x2 + 8x – 48 = 0 by completing the square. Show your work for full credit.
anonymous
 4 years ago
Solve x2 + 8x – 48 = 0 by completing the square. Show your work for full credit.

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radar
 4 years ago
Best ResponseYou've already chosen the best response.2For completing the square the coefficient of the "squared" term should be 1 and it is.

radar
 4 years ago
Best ResponseYou've already chosen the best response.2The term to be added to make it a perfect square is one half of the coefficent of the x term squared.

radar
 4 years ago
Best ResponseYou've already chosen the best response.2What you add you must also subtract to retain the equations original value.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[(x^2+8x+16)1648\] < just added and substracted 4, which is \[(8/2)^2\] Now try to factor out the term in brackets what do you get?

radar
 4 years ago
Best ResponseYou've already chosen the best response.2Lets see how saljudieh07 did this

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry \[4^2\] that is what I added and substracted

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now, kaymarie12479 can you factor the expression in the brackets?

radar
 4 years ago
Best ResponseYou've already chosen the best response.2Actually you want to the square root of the value in the brackets. The origiinal equation is factorable, but you want to "complete the square. \[(x + 4)^{2}=64\]

radar
 4 years ago
Best ResponseYou've already chosen the best response.2Note the original equation is factorable (x4)(x+12)=0 however, they want you to use completing the square method.

radar
 4 years ago
Best ResponseYou've already chosen the best response.2Note. That factoring gives you x=4 and x=12 as answer and x + 4 = +/ 8 gives same results x=4, and x=12

radar
 4 years ago
Best ResponseYou've already chosen the best response.2@saljudieh07 you left off the "=0" and disregarded your constants.
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