anonymous
  • anonymous
Solve x2 + 8x – 48 = 0 by completing the square. Show your work for full credit.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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radar
  • radar
For completing the square the coefficient of the "squared" term should be 1 and it is.
radar
  • radar
The term to be added to make it a perfect square is one half of the coefficent of the x term squared.
radar
  • radar
What you add you must also subtract to retain the equations original value.

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anonymous
  • anonymous
\[(x^2+8x+16)-16-48\] <---- just added and substracted 4, which is \[(8/2)^2\] Now try to factor out the term in brackets what do you get?
radar
  • radar
Lets see how saljudieh07 did this
radar
  • radar
Looks good.
anonymous
  • anonymous
sorry \[4^2\] that is what I added and substracted
anonymous
  • anonymous
now, kaymarie12479 can you factor the expression in the brackets?
radar
  • radar
Actually you want to the square root of the value in the brackets. The origiinal equation is factorable, but you want to "complete the square. \[(x + 4)^{2}=64\]
radar
  • radar
\[x+4=\pm8\]
radar
  • radar
Note the original equation is factorable (x-4)(x+12)=0 however, they want you to use completing the square method.
radar
  • radar
Note. That factoring gives you x=4 and x=-12 as answer and x + 4 = +/- 8 gives same results x=4, and x=-12
radar
  • radar
@saljudieh07 you left off the "=0" and disregarded your constants.

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