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anonymous
 4 years ago
PQRS is a diameter of a circle of radius 6cm. the lengths PQ , QR , and RS are equal .Semicircles are drawn on PQ and QS as diameters. Find the perimeter of the shaded region ??
anonymous
 4 years ago
PQRS is a diameter of a circle of radius 6cm. the lengths PQ , QR , and RS are equal .Semicircles are drawn on PQ and QS as diameters. Find the perimeter of the shaded region ??

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328409572620:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok so to get the answer you need to first: find the parameter of the whole circle, find the parameter of the circle with diameter PQ and find the parameter of the circle with diameter QS when you are down these let me know. i will be back to help you

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hmmmmmm kkk thnx anyway !!!!!!

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0The indicated region is half the circumference of the outer circle: dw:1328410059872:dw

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0The next indicated region is half the circumference of the circle with diameter PQ: dw:1328410111834:dw

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0finally, the indicated region is half the circumference of the circle with diameter QS: dw:1328410162923:dw

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0add up all three and you have your answer. that is what @saljudieh07 was trying to show you.

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0there is no "then"  add up all three and you have your answer.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohhhh thnx no then !!!!!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328410363505:dw

asnaseer
 4 years ago
Best ResponseYou've already chosen the best response.0:) you are more than welcome!
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