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anonymous

  • 4 years ago

If the altitude of an equilateral triangle is 12cm, find its area.. According to the answer sheet, answer is 83.1cm^2

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  1. anonymous
    • 4 years ago
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    yeah looks good to me

  2. anonymous
    • 4 years ago
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    Erm.. How do you solve it?

  3. anonymous
    • 4 years ago
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    |dw:1328411891637:dw|

  4. anonymous
    • 4 years ago
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    you need the base. now since this is an equilateral triangle, all sides are equal. and that is what we are looking for, one of the sides. lets call is it x|dw:1328412007974:dw|

  5. anonymous
    • 4 years ago
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    ok..

  6. anonymous
    • 4 years ago
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    then pythagoras tells you that \[(\frac{1}{2}x)^2+12^2=x^2\] \[12^2=x^2-\frac{1}{4}x^2\] \[144=\frac{3}{4}x^2\] \[x^2=144\times \frac{4}{3}=192\] \[x=\sqrt{192}=6\sqrt{3}\]

  7. anonymous
    • 4 years ago
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    |dw:1328412341534:dw|

  8. anonymous
    • 4 years ago
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    |dw:1328423226163:dw|

  9. anonymous
    • 4 years ago
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    |dw:1328423349746:dw|

  10. anonymous
    • 4 years ago
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    |dw:1328423488080:dw|

  11. anonymous
    • 4 years ago
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    Thank you :)

  12. anonymous
    • 4 years ago
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    yw

  13. anonymous
    • 4 years ago
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    ? yw?

  14. anonymous
    • 4 years ago
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    your welcome

  15. anonymous
    • 4 years ago
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    Oh I didn't know :P We usually use np (no problem) in Sg

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