anonymous
  • anonymous
Consider a w-N weight suspended by two wires as shown in the accompanying figure. If the magnitude of the vector F sub 2 is 110 N, find w and the vector F sub 1:
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
|dw:1328415051107:dw|
anonymous
  • anonymous
thats what i am trying to find
anonymous
  • anonymous
F2 is 110 N as stated in my problem

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bahrom7893
  • bahrom7893
wait what are u trying to find?
anonymous
  • anonymous
right, but i need to find w=weight of obejct and magnitude of F sub 1
anonymous
  • anonymous
physics?
anonymous
  • anonymous
that is how the problem is written
anonymous
  • anonymous
i believe a system should solve this, with the understanding f sub 1 + F sub 2=w, cant seem too put it together though
anonymous
  • anonymous
how about ratio and proportion to find the value of the magnitude of F sub 1|dw:1328416025545:dw| you can find the value of F sub 1. and since you said that F sub 1 + F sub 2=w, plug the values to find weight. . but i'm not sure. .
anonymous
  • anonymous
what answer do you get for the magnitude of Fsub 1
anonymous
  • anonymous
|dw:1328416246651:dw| i don't have calculator. .
anonymous
  • anonymous
i have 124.47 N
anonymous
  • anonymous
the answer was 148.554..
anonymous
  • anonymous
break it into components. Vector(F1)+vector(f2)+vector(w)=0. Vector f1=magf1<-cos(t1),Sin(t1)> Vector f2=magf2 X components add to zero -magf1cos(43)+110cos(38)=0 Solve for magf1 and plug into: y components: magf1sin(43)+110sin(38)=w
anonymous
  • anonymous
and that made me wrong. .lol
anonymous
  • anonymous
how do the x components add to zero
anonymous
  • anonymous
instantaneously/or not hah is not in motion. There is no movement in the x direction. Weight is a downward vector so it has no x component. Thus F1 and F2's x components add to zero.
anonymous
  • anonymous
im am still not sure
anonymous
  • anonymous
d|dw:1328417056124:dw| You have these three vectors to worry about. Adding the x components gives you zero even if you include the weight vector because as you can see in the picture weight has a x-component of zero.
anonymous
  • anonymous
they add to zero because there is no movement.
anonymous
  • anonymous
there is also no movement in the y direction but weight has a -y component.
anonymous
  • anonymous
even if they have different angles, like cos43 and cos 38
anonymous
  • anonymous
those indicate the direction of the vectors. Multiplying them by the magnitude will give you your components.
anonymous
  • anonymous
Notice how I put magf1<-x,y> for vector f1. That vector has a negative x component.
anonymous
  • anonymous
So in my example, based on how you did it, my magnitude for f1 would be given by:|dw:1328417583344:dw|
anonymous
  • anonymous
?
anonymous
  • anonymous
Did you say you have the answers to this problem?
anonymous
  • anonymous
but yes that should be the magnitude of f1 by algebraic methods
anonymous
  • anonymous
its like 148.55...something
anonymous
  • anonymous
for the weight right?
anonymous
  • anonymous
yes for the weight
anonymous
  • anonymous
okay yeah you should be getting 118.52.. for f1
anonymous
  • anonymous
more importantly do you understand?
anonymous
  • anonymous
yes i do thank you very much

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