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thats what i am trying to find
F2 is 110 N as stated in my problem
wait what are u trying to find?
right, but i need to find w=weight of obejct and magnitude of F sub 1
that is how the problem is written
i believe a system should solve this, with the understanding f sub 1 + F sub 2=w, cant seem too put it together though
how about ratio and proportion to find the value of the magnitude of F sub 1|dw:1328416025545:dw| you can find the value of F sub 1. and since you said that F sub 1 + F sub 2=w, plug the values to find weight. . but i'm not sure. .
what answer do you get for the magnitude of Fsub 1
|dw:1328416246651:dw| i don't have calculator. .
i have 124.47 N
the answer was 148.554..
break it into components. Vector(F1)+vector(f2)+vector(w)=0. Vector f1=magf1<-cos(t1),Sin(t1)> Vector f2=magf2
X components add to zero
Solve for magf1 and plug into:
and that made me wrong. .lol
how do the x components add to zero
instantaneously/or not hah is not in motion. There is no movement in the x direction. Weight is a downward vector so it has no x component. Thus F1 and F2's x components add to zero.
im am still not sure
d|dw:1328417056124:dw| You have these three vectors to worry about. Adding the x components gives you zero even if you include the weight vector because as you can see in the picture weight has a x-component of zero.
they add to zero because there is no movement.
there is also no movement in the y direction but weight has a -y component.
even if they have different angles, like cos43 and cos 38
those indicate the direction of the vectors. Multiplying them by the magnitude will give you your components.
Notice how I put magf1<-x,y> for vector f1. That vector has a negative x component.
So in my example, based on how you did it, my magnitude for f1 would be given by:|dw:1328417583344:dw|
Did you say you have the answers to this problem?
but yes that should be the magnitude of f1 by algebraic methods
its like 148.55...something
for the weight right?
yes for the weight
okay yeah you should be getting 118.52.. for f1
more importantly do you understand?
yes i do thank you very much