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## anonymous 4 years ago In Cu + HNO3 to CU2 + NO2 + H2O, deduce the oxidation state of all the elements on both reactant and product side.

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1. Xishem

$Cu+HNO_3 \rightarrow Cu^{2+}+NO_2+H_2O$LHS: Cu: 0 H: +1 N: +5 O: -2 RHS: Cu:+2 N: +4 O: -2 H: +1 O:-2

2. anonymous

So which reactant was oxidised and which was reduced?

3. anonymous

Thankyou for your help :-)

4. Xishem

Well, the species that is oxidized is the species whose oxidation state is raised. The opposite is true for the species that is reduced. Therefore... Copper is the reactant that is oxidized, and Nitrogen is the reactant that is reduced.

5. anonymous

Greatr! That is really helpful, thankyou. Maybe you can help me on another organic chem question I've been attempting. I'm trying to work out the functional groups of the compounds that make up Nyolon/. So far I have Amine, Alkane and Carboxylic Acid. Is that right?

6. anonymous

Sorry, I meant Nylon.

7. Xishem

I'm sorry. I can't help you with that. I've never taken an organic chem class.

8. anonymous

That's ok. I appreciate your help. The only other question I have been struggling with for hours is calculating the pH for weak acids... could you help me with that?

9. anonymous

For example... 2.5M NH3

10. Xishem

Actually, I'm unable to help you as we JUST started our Acids and Bases chapter in my Chem 2 class (:. I'd certainly be able to help you after this Monday, when our lecture over weak acids will be, though :P

11. anonymous

Haha that would be great!

12. anonymous

missem your nylon functional groups are correct. you could add lactams to it(Cyclic amides:- Used in production on nylon 6)

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