• anonymous
I am asked to find the equation of the tangent line to the curve f(x)=sin(x)+sin^2(x) at the point (0,0). Can anyone explain how I should approach this problem? I understand that I must differentiate the function, but I can't see how to come up with the equation for the line. Any help would be greatly appreciated.
  • Stacey Warren - Expert
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
  • katieb
I got my questions answered at in under 10 minutes. Go to now for free help!
  • Zarkon
can you find the derivative?
  • dumbcow
equation of the line: y = mx+b m = f'(0) **slope is derivative at point (0,0) b = y-mx = 0-f'(0)*0 = 0 --> y = f'(0)x all you need to do is find f'(x)
  • anonymous
slope point form: slope=m point: (x,y) y-y2=m(x-x1) slope=f'[0] point: (0,0) y-0=(f'[x])(x-0)

Looking for something else?

Not the answer you are looking for? Search for more explanations.