A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
At 7 am Joe starts sprinting at 6 miles per hour. At 7:10 am, Ken starts off after him. How fast must Ken run in order to overtake him at 7:30 am?
anonymous
 4 years ago
At 7 am Joe starts sprinting at 6 miles per hour. At 7:10 am, Ken starts off after him. How fast must Ken run in order to overtake him at 7:30 am?

This Question is Closed

dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.19 mph 1/3*r = 1/2*6 r = 9

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hence for joe: 6t=d (where t is time, and d is distance) for Ken: v=d/(20/60) no we know that after 30 minutes that's when ken is supposed to catch up that joe has already ran a distance of: 6*0.5=d, d=3miles substitute that back into v=d(3) then, speed of ken should be =3*3= 9 miles an hour
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.