anonymous
  • anonymous
A(1,3) B(-3,5) find the perpendicular bisector equation
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
i know the slope is -2
anonymous
  • anonymous
Find the midpoint also, the perpendicular line will pass through this point.
anonymous
  • anonymous
the midpoint is -1,4

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
So can you write an equation for a line that passes through (-1,4) with a slope of 1/2?
anonymous
  • anonymous
so it would be y-4 = 1 x-(-1) = 2 ?
anonymous
  • anonymous
if slope is -2 of the original line given two vertices,therefor the slope of the perpendicular line is 1/2
anonymous
  • anonymous
the answer is 2x - y = -6 but i get a different answer
ash2326
  • ash2326
We have the line connecting the points A(1,3) and B(-3,5) the point which divides the line into two halves will have coordinates D(x1,y1) \[ x1= \frac{1+(-3)}{2}\] and \[y1=\frac{3+5}{2}\] so we get \[(x1,y1= (-2, 4)\] so the perpendicular bisector will pass through this point and we need one more condition like another point or slope to find out its equation here it's easy to find the slope of perependicular bisector Let the slope of AB be m1 and of the perpendicular bisector be m2 \[m1= \frac{5-3}{-3-1}\] we get \[m1= -\frac{1}{2}\] now since AB and its perpendicular bisector are perpendicular to each other \[ m1*m2=-1\] so \[m2=2\] so we have the slope m2= 2 and the line passes through D(-2, 4) so equation will be \[ \frac{y-4}{x+2}= 2\] so we get \[y-4=2x+2\] so the equation is \[y-2x+6\]
ash2326
  • ash2326
\[ y-2x=6\]
ash2326
  • ash2326
or it can be written as \[2x-y=-6\]
anonymous
  • anonymous
isnt the mid point (-1,4)?
anonymous
  • anonymous
1 + (-3) = -2 then -2 / 2 = -1
anonymous
  • anonymous
since the question is the perpendicular bisector equation of the line, we will be needing the midpoint and the perpendicular slope. .
ash2326
  • ash2326
sorry I made a mistake then you'll get \[ \frac{y-4}{x+1}=2\] or \[y-4=2x+2\] or \[y-2x=6\] i made mistake 2 times and fortunately got the correct answer:)
anonymous
  • anonymous
nikkyster if you got the slope to =2, you calculated the slope wrong
anonymous
  • anonymous
The slope of the original line is -1/2
anonymous
  • anonymous
i got the slope to be -2
ash2326
  • ash2326
yeah slope of line is \[-\frac{1}{2}\]
anonymous
  • anonymous
I should've double checked it earlier ;p
anonymous
  • anonymous
But you have the right midpoint
anonymous
  • anonymous
yeah your right ! i got the slope wrong
anonymous
  • anonymous
what about for midpoint with a decimal?
anonymous
  • anonymous
|dw:1328422479768:dw||dw:1328422542891:dw||dw:1328422687105:dw| therefor the perpendicular slope is 2, the equation of the perpendicular line is
anonymous
  • anonymous
|dw:1328422920367:dw|
anonymous
  • anonymous
A(3,1) B(-3,6)
anonymous
  • anonymous
the midpoint is (0,3.5) and the slope would be -5/6
anonymous
  • anonymous
is this another problem?
anonymous
  • anonymous
yes
anonymous
  • anonymous
what's the question? prependicular equation?
anonymous
  • anonymous
perpendicular ?

Looking for something else?

Not the answer you are looking for? Search for more explanations.