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anonymous
 4 years ago
A(1,3) B(3,5)
find the perpendicular bisector equation
anonymous
 4 years ago
A(1,3) B(3,5) find the perpendicular bisector equation

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i know the slope is 2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Find the midpoint also, the perpendicular line will pass through this point.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So can you write an equation for a line that passes through (1,4) with a slope of 1/2?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so it would be y4 = 1 x(1) = 2 ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if slope is 2 of the original line given two vertices,therefor the slope of the perpendicular line is 1/2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the answer is 2x  y = 6 but i get a different answer

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.1We have the line connecting the points A(1,3) and B(3,5) the point which divides the line into two halves will have coordinates D(x1,y1) \[ x1= \frac{1+(3)}{2}\] and \[y1=\frac{3+5}{2}\] so we get \[(x1,y1= (2, 4)\] so the perpendicular bisector will pass through this point and we need one more condition like another point or slope to find out its equation here it's easy to find the slope of perependicular bisector Let the slope of AB be m1 and of the perpendicular bisector be m2 \[m1= \frac{53}{31}\] we get \[m1= \frac{1}{2}\] now since AB and its perpendicular bisector are perpendicular to each other \[ m1*m2=1\] so \[m2=2\] so we have the slope m2= 2 and the line passes through D(2, 4) so equation will be \[ \frac{y4}{x+2}= 2\] so we get \[y4=2x+2\] so the equation is \[y2x+6\]

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.1or it can be written as \[2xy=6\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0isnt the mid point (1,4)?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.01 + (3) = 2 then 2 / 2 = 1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0since the question is the perpendicular bisector equation of the line, we will be needing the midpoint and the perpendicular slope. .

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.1sorry I made a mistake then you'll get \[ \frac{y4}{x+1}=2\] or \[y4=2x+2\] or \[y2x=6\] i made mistake 2 times and fortunately got the correct answer:)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0nikkyster if you got the slope to =2, you calculated the slope wrong

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The slope of the original line is 1/2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i got the slope to be 2

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.1yeah slope of line is \[\frac{1}{2}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I should've double checked it earlier ;p

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0But you have the right midpoint

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah your right ! i got the slope wrong

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what about for midpoint with a decimal?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328422479768:dwdw:1328422542891:dwdw:1328422687105:dw therefor the perpendicular slope is 2, the equation of the perpendicular line is

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328422920367:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the midpoint is (0,3.5) and the slope would be 5/6

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is this another problem?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what's the question? prependicular equation?
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