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anonymous
 4 years ago
an aqueous solution of potassium carbonate combine with a solution of calcium nitrate.
what are the total and net ionic equation?
anonymous
 4 years ago
an aqueous solution of potassium carbonate combine with a solution of calcium nitrate. what are the total and net ionic equation?

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Xishem
 4 years ago
Best ResponseYou've already chosen the best response.2\[K_2CO_3(aq)+Ca(NO_3)_2(aq) \rightarrow \ ?\]If we break these two reactants up into their respective ions, we get...\[K^++CO_3^{2}+Ca^{2+}+NO_3^{}\]If we combine the anion of one reactant with the cation of the other and viceversa, we get...\[CaCO_3+KNO_3\]Now we need to ask ourselves if either of these is soluble in water. Based on solubility rules, we know that all nitrates are soluble, so the potassium nitrate is. Alternatively, we know that all carbonates are insoluble except those of sodium, potassium, and ammonium; therefore, this calcium carbonate is insoluble. This is good. It means we have a driving force for the reaction! That driving force is that a precipitate will form. In such a case, a precipitation reaction will occur, and the total equation will be...\[K_2CO_3(aq)+Ca(NO_3)_2(aq) \rightarrow CaCO_3(s)+2KNO_3(aq)\]To determine the net ionic equation, we need to remove all ions that appear on both sides of the equation in aqueous solution  these ions are called spectator ions, and do not actually undergo any chemical reaction. To determine the net ionic equation, let's first rewrite the equation in terms of ions...\[2K^+(aq)+CO_3^{2}(aq)+Ca^{2+}(aq)+2NO_3^{}(aq) \rightarrow Ca^{2+}(s)+CO_3^{2}(s)+2K^+(aq)+2NO_3^(aq)\]The species that appear in aqueous solution on both sides of the equation (spectator ions) are... \[2K^+,NO_3^\]If we remove these spectator ions from the total equation, we will get the net ionic equation...\[CO_3^{2}(aq)+Ca^{2+}(aq) \rightarrow CaCO_3(s)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thanks you really break things down i greatly appreciat it

Xishem
 4 years ago
Best ResponseYou've already chosen the best response.2No problem. If you are uncertain of the meaning about anything I've described, feel free to ask (:.
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