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anonymous
 4 years ago
2 ferryboats started at the same instant from opposite sides of a river, traveling across the water at right angles to the shore. They first met 720 yards from the nearest shore and, on reaching the opposite side, spent 10 minutes in the slip before starting back. They met again 400 yards from the nearest shore. What is the width of the river?
anonymous
 4 years ago
2 ferryboats started at the same instant from opposite sides of a river, traveling across the water at right angles to the shore. They first met 720 yards from the nearest shore and, on reaching the opposite side, spent 10 minutes in the slip before starting back. They met again 400 yards from the nearest shore. What is the width of the river?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If the first boat has speed v1 and the second has v2. Let the width be x. The first boat has travelled 720m. The second x720. They have travelled for same time so 720/v1=(x720)/v2. v2/v1=(x720)/720. Similarly the second time, 400/v2=(x400)/v1. v2/v1=400/x400. so (x720)(x400)=720*400. Solve the quadratic.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0could you elaborate it further? it's complicated. . .

y2o2
 4 years ago
Best ResponseYou've already chosen the best response.0If there velocity were the same in the i the two times , they would have met at the same distance from the nearest shore in the two times.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok. dw:1328425736975:dw So here velocity = distance/time. The time they travel to meet each other is same as they started out at the same time.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0why did you use x720?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Because thats the distance travelled by the second boat.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you mean the second boat travel lesser than the 2nd?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Maybe, May not be it depends on x, if x is greater than 1540 then the second travelled more if it is lesser than that then the first travelled more.Thats not an issue.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wer did you get 1540? i'm confused now?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ah screw the 1540. It does not matter how much each boat has travelled .U just need to find the width x. Why are breaking your head over unnecassry things?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the answer is 1120yds.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0solve the quadratic that shankvee\ posted earlier.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0aah. . thank you all. . that's why i'm asking lots of questions because i have to defend my answer. .

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I would prefer shankvee without the '\'.... LOL....

y2o2
 4 years ago
Best ResponseYou've already chosen the best response.0can somebody answer my question ?!

y2o2
 4 years ago
Best ResponseYou've already chosen the best response.0If there velocity were the same in the i the two times , they would have met at the same distance from the nearest shore in the two times.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well actually i think the question does not imply neearest shore it means opposite shores.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If v1 equals v2 then the ratio is 1 where they met would be the same distance which would equal half the width. basically, they would meet halfway in between if they are going the same velocity.
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