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anonymous

  • 4 years ago

2 ferryboats started at the same instant from opposite sides of a river, traveling across the water at right angles to the shore. They first met 720 yards from the nearest shore and, on reaching the opposite side, spent 10 minutes in the slip before starting back. They met again 400 yards from the nearest shore. What is the width of the river?

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  1. anonymous
    • 4 years ago
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    If the first boat has speed v1 and the second has v2. Let the width be x. The first boat has travelled 720m. The second x-720. They have travelled for same time so 720/v1=(x-720)/v2. v2/v1=(x-720)/720. Similarly the second time, 400/v2=(x-400)/v1. v2/v1=400/x-400. so (x-720)(x-400)=720*400. Solve the quadratic.

  2. anonymous
    • 4 years ago
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    could you elaborate it further? it's complicated. . .

  3. anonymous
    • 4 years ago
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    pleaseee.

  4. y2o2
    • 4 years ago
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    If there velocity were the same in the i the two times , they would have met at the same distance from the nearest shore in the two times.

  5. anonymous
    • 4 years ago
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    Ok. |dw:1328425736975:dw| So here velocity = distance/time. The time they travel to meet each other is same as they started out at the same time.

  6. anonymous
    • 4 years ago
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    why did you use x-720?

  7. anonymous
    • 4 years ago
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    Because thats the distance travelled by the second boat.

  8. anonymous
    • 4 years ago
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    you mean the second boat travel lesser than the 2nd?

  9. anonymous
    • 4 years ago
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    Maybe, May not be it depends on x, if x is greater than 1540 then the second travelled more if it is lesser than that then the first travelled more.Thats not an issue.

  10. anonymous
    • 4 years ago
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    wer did you get 1540? i'm confused now?

  11. anonymous
    • 4 years ago
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    Ah screw the 1540. It does not matter how much each boat has travelled .U just need to find the width x. Why are breaking your head over unnecassry things?

  12. dumbcow
    • 4 years ago
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    the answer is 1120yds.

  13. anonymous
    • 4 years ago
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    how? @dumbcow..

  14. dumbcow
    • 4 years ago
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    solve the quadratic that shankvee\ posted earlier.

  15. anonymous
    • 4 years ago
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    aah. . thank you all. . that's why i'm asking lots of questions because i have to defend my answer. .

  16. anonymous
    • 4 years ago
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    I would prefer shankvee without the '\'.... LOL....

  17. dumbcow
    • 4 years ago
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    then why put it?

  18. y2o2
    • 4 years ago
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    can somebody answer my question ?!

  19. dumbcow
    • 4 years ago
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    what question? @y202

  20. y2o2
    • 4 years ago
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    If there velocity were the same in the i the two times , they would have met at the same distance from the nearest shore in the two times.

  21. anonymous
    • 4 years ago
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    at shankvee\

  22. anonymous
    • 4 years ago
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    Well actually i think the question does not imply neearest shore it means opposite shores.

  23. dumbcow
    • 4 years ago
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    If v1 equals v2 then the ratio is 1 where they met would be the same distance which would equal half the width. basically, they would meet halfway in between if they are going the same velocity.

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