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anonymous

  • 4 years ago

if 6.47 moles of potassium chlorate is used in the reaction shown below, how many moles of C12H22O11 would also be used? 8KCLO3 (s) C12H22O11 (s) => 8KCl (s) + 12CO2 (g) + 11H2O(g)

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  1. Xishem
    • 4 years ago
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    This is another mole-mole conversion. Hint: For every 8 moles of KCLO3 that are consumed, how many moles of C12H22O11 will be consumed?

  2. anonymous
    • 4 years ago
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    1

  3. Xishem
    • 4 years ago
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    Ok, so now you have a conversion factor to convert between moles of KCLO3 and C12H22O11 and vice-versa...\[\frac{1mol\ C_{12}H_{22}O_{11}}{8mol\ KCLO_3}=1\]

  4. anonymous
    • 4 years ago
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    ok so is it (6.47)(1/8)?

  5. Xishem
    • 4 years ago
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    Yep (:. And you can always check yourself by making sure your units cancel. In this moles of KCLO3 cancel, and you are left with moles of sucrose.

  6. anonymous
    • 4 years ago
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    thanks again

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