According to the fundamental theorem of algebra, how many zeros does the polynomial below have? f(x)=x³-10x²+27-12

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According to the fundamental theorem of algebra, how many zeros does the polynomial below have? f(x)=x³-10x²+27-12

Mathematics
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3
It can have atmost 3 zeroes..
why at-most? it is precisely 3.

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Other answers:

Any polynomial of degree n ... has n roots but you may need to use complex numbers.
Any polynomial of degree n ... has n complex roots.
All complex are real with the coefficient of imaginary part as zero ;)

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