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anonymous

  • 4 years ago

Al saves pennies. Al agreed to give 3/5 of his pennies to Bev if she would give 3/5 of what she got from Al to Carl and if Carl in turn would give 3/5 of what he got from Bev to Dani. Bev, Carl, and Dani received 189 pennies. How many pennies did Al have initially?

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  1. anonymous
    • 4 years ago
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    what's a penny? a coin? i don't know american coins. .

  2. anonymous
    • 4 years ago
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    a penny is one cent .01

  3. anonymous
    • 4 years ago
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    neways it makes no diff

  4. anonymous
    • 4 years ago
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    I gtg sorry i cant help out :(

  5. anonymous
    • 4 years ago
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    It is a coin.

  6. anonymous
    • 4 years ago
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    The answer was not correct. I'm sorry if you misunderstood, the question asks how many coins Al had to begin with.

  7. anonymous
    • 4 years ago
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    is it 189 each?

  8. anonymous
    • 4 years ago
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    does bec, carl and dani received 189 each?

  9. anonymous
    • 4 years ago
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    Click 0.JPG first then 00.JPG. This is an example only using different numbers. I am not understanding the example.

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  10. anonymous
    • 4 years ago
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    If only Dani received 189 pennies, then Al started with 875. If all 3 of them combined received 189 pennies, Al had 315

  11. Directrix
    • 4 years ago
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    875. (27/125) P = 189. P = 875

  12. anonymous
    • 4 years ago
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    let x be the amount Al started with x*3/5=amount Bev has x*3/5*3/5=amount Carl has x*3/5*3/5*3/5=amount Dani has so 189=x*3/5*3/5*3/5 x=875

  13. anonymous
    • 4 years ago
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    Thank you!! This was sucking the life out of me. ;D

  14. anonymous
    • 4 years ago
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    The wording of the problem is retarded. It makes it look like all 3 combined got 189.

  15. anonymous
    • 4 years ago
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    It totally is!

  16. anonymous
    • 4 years ago
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    3/5x + 3/5(3/5x) + 3/5[3/5(3/5x)]=x+189 is my representation correct??

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