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anonymous
 4 years ago
Please help.I am confused!
Inside a square ABCD construct the equilateral triangles ABK,CDM,and DAN.Prove that the midpoints of the segments KL,LM,MN,NK and those of AN,AK,BK,BL,CL,CM,DM, and DN are the vertices of a regular dodecagon.
anonymous
 4 years ago
Please help.I am confused! Inside a square ABCD construct the equilateral triangles ABK,CDM,and DAN.Prove that the midpoints of the segments KL,LM,MN,NK and those of AN,AK,BK,BL,CL,CM,DM, and DN are the vertices of a regular dodecagon.

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Directrix
 4 years ago
Best ResponseYou've already chosen the best response.0Wondering where the points K, M, and N are located?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes one picture may be importantly  i think

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.0Click on "Draw" and sketch it , please.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0L is an arbitrary point?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I think you forgot a triangle BCL

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328433505949:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so this is like there this ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I think it's something like this.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'll try to solve this.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0SqueeSpleen  ATTENTION  this exersice begin with the word ,,inside a square ..."  so i think that in this way your picture not can being right,correct how do you think ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Inside... :( I'm horrible with English. I'll make a new draw.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0We can Prove Angles are equal all of them it is very easy onlt the figure is complicated

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Distances neednot be found

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I have a proof using complex numbers but I want a purely geometric proof.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm wanting to use trigonometry :p, that's why I'm using distances to figure out the angles.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0KM=(12(1cos(30)))CB distance between mid point kn and midpoint nm=KM/2 I forget the parenthesis. the first time.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Take only two adjacent angle and try to proof them equal I have done it Then you can use symetry argument to extend it to all adjacent pairs

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Label all points and I shall show you

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm horrible with geometry but I'll label all points and left it to you. Geometry problems were the problems who gave me the worst times when I was in my countrys maths olympiads :( I named the mid points of the segments after their extrems.
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