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anonymous
 4 years ago
Challenge:
Find the ratio of area of triangle and area of triangle formed using the lengths of the medians.
anonymous
 4 years ago
Challenge: Find the ratio of area of triangle and area of triangle formed using the lengths of the medians.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sorry it is not a challenge it took me 2mins to realize the solution

Directrix
 4 years ago
Best ResponseYou've already chosen the best response.0If we're talking a single triangle, the area would be constant and the ratio 1:1.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0area of the triangle of medians is threefourths of the area of the given triangle.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0three medians of a triangle divide the triangle into six equal areas.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0However tell me how did you do it just want to check if we both used the same method

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I used this: http://mathworld.wolfram.com/TriangleMedian.html

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I know a proof using vectors

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Aha, vector would certainly make things much easy.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It is a 3 line proof And i discovered it myself

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Furthermore, the area of the triangle is : \[1/3\sqrt{(2\sum u ^{2}v ^{2}  \sum u^{4})}\] where u,v and w are the medians .

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@Aron that's a fairly complicated form.
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