Challenge: Find the ratio of area of triangle and area of triangle formed using the lengths of the medians.

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Challenge: Find the ratio of area of triangle and area of triangle formed using the lengths of the medians.

Mathematics
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Sorry it is not a challenge it took me 2mins to realize the solution
If we're talking a single triangle, the area would be constant and the ratio 1:1.
No

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area of the triangle of medians is three-fourths of the area of the given triangle.
three medians of a triangle divide the triangle into six equal areas.
That is right aron
However tell me how did you do it just want to check if we both used the same method
Yep it's 3/4.
I used this:http://mathworld.wolfram.com/TriangleMedian.html
I know a proof using vectors
Aha, vector would certainly make things much easy.
It is a 3 line proof And i discovered it myself
Furthermore, the area of the triangle is : \[1/3\sqrt{(2\sum u ^{2}v ^{2} - \sum u^{4})}\] where u,v and w are the medians .
@Aron that's a fairly complicated form.

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