a!+b! = a^b

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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I can be rewritten using the gamma function as: \[\Gamma(a+1) + \Gamma(b+1) = a^{b}\]
Any idea how to solve this?
As you might know this is my problem which I posted here http://math.stackexchange.com/questions/105923/

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I have a feeling that the proving that only (2,2) and (2,3) are the only solutions is somewhat difficult.
Try using the gamma function.
So you have a solution Aron?
nic question aron
No,I don't have a solution but I was just wondering if I could solve it using the gamma function.
Dig deep into that Wikipedia page.
\[\Gamma (Z) = \int\limits\limits_{0}^{\infty}e^{-t}t^{z-1}dt\]
$$\stackrel{\circ.\circ}{\huge o}\angle\huge\lbrace\normalsize\text{I am tired, time for a nap! } $$
Is there a way to format text in the math formatter so it isn't italicized?
\text{}
The graph looks weird!
http://www.wolframalpha.com/input/?i=Solve%20a!%20%2B%20b!%20%3D%20a%5Eb&t=crmtb01
It looks like an alien spaceship
haha :D
yeah
Anyone able to solve it yet?
Cool graph! You guys are so funny!

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