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anonymous
 4 years ago
How do I solve: 4y^2  11y  3 =0 by factoring?
anonymous
 4 years ago
How do I solve: 4y^2  11y  3 =0 by factoring?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You should use quadratic formula for this.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but I have to use factoring.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328452241616:dw

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1factoring means to undo multiplication

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1we have to put this into a form that can be unproducted lol

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1a product is the result of multiplying; to undo multiplication means to factor it out again

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.13*2 produces 6 6 factors into 3 and 2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well I sort of factored but I have questions..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.04y^2  11y  3 = 4y^2 + y  12y  3 = y(4y + 1)  3(4y + 1) = (4y + 1)(y  3)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1there are a few algorithms for factoring quadratics; pratu did factor by grouping there :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0But the point is: how does it help in solving the equation?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.04y^2  12y + y  3=0 4y (y3) + (y3) = 0 (y3) (4y+1) = 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but... I don't get why it's "(y3)(4y + 1) =0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0like from 4y (y3)+(y3) to (y3)(4y + 1) =0

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1a(b+c) = ab + ac ab + ac = a(b+c)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1your fatoring out a (y3) in this case

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohhhh. factoring a y3?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1grouping allows you to "see" the common factor of (y3) right?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1then factor it out ....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(4y + 1)(y  3) = 0 dw:1328452809130:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohhh.. I think I'm getting it, ugh. Why is math so difficult for me >_<

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1you have 2 terms: 4y (y3) and 1(y3) the GCF is (y3)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.14(2) + 1(2) is the same as 2(4+1) right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but why is it (y3)(4y+1) now? o.o

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1well, in this case it aint a 2, its (y3)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328452856397:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Does it help in any way?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.04y = (y + 4)/(y  3)
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