anonymous
  • anonymous
How do I solve: 4y^2 - 11y - 3 =0 by factoring?
Mathematics
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
You should use quadratic formula for this.
anonymous
  • anonymous
but I have to use factoring.
anonymous
  • anonymous
|dw:1328452241616:dw|

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

amistre64
  • amistre64
factoring means to undo multiplication
anonymous
  • anonymous
okay
amistre64
  • amistre64
we have to put this into a form that can be unproducted lol
anonymous
  • anonymous
hm?
amistre64
  • amistre64
a product is the result of multiplying; to undo multiplication means to factor it out again
anonymous
  • anonymous
ohh. okay.
amistre64
  • amistre64
3*2 produces 6 6 factors into 3 and 2
anonymous
  • anonymous
Well I sort of factored but I have questions..
anonymous
  • anonymous
4y^2 - 11y - 3 = 4y^2 + y - 12y - 3 = y(4y + 1) - 3(4y + 1) = (4y + 1)(y - 3)
amistre64
  • amistre64
there are a few algorithms for factoring quadratics; pratu did factor by grouping there :)
anonymous
  • anonymous
okay..
anonymous
  • anonymous
how about this:
anonymous
  • anonymous
But the point is: how does it help in solving the equation?
anonymous
  • anonymous
4y^2 - 12y + y - 3=0 4y (y-3) + (y-3) = 0 (y-3) (4y+1) = 0
amistre64
  • amistre64
same results :)
anonymous
  • anonymous
but... I don't get why it's "(y-3)(4y + 1) =0
amistre64
  • amistre64
undistributing
anonymous
  • anonymous
like from 4y (y-3)+(y-3) to (y-3)(4y + 1) =0
amistre64
  • amistre64
a(b+c) = ab + ac ab + ac = a(b+c)
amistre64
  • amistre64
your fatoring out a (y-3) in this case
anonymous
  • anonymous
ohhhh. factoring a y-3?
amistre64
  • amistre64
yep
anonymous
  • anonymous
what do you mean?
amistre64
  • amistre64
grouping allows you to "see" the common factor of (y-3) right?
anonymous
  • anonymous
yes
amistre64
  • amistre64
then factor it out ....
anonymous
  • anonymous
(4y + 1)(y - 3) = 0 |dw:1328452809130:dw|
anonymous
  • anonymous
ohhh.. I think I'm getting it, ugh. Why is math so difficult for me >_<
amistre64
  • amistre64
you have 2 terms: 4y (y-3) and 1(y-3) the GCF is (y-3)
anonymous
  • anonymous
ohh, it is.
amistre64
  • amistre64
4(2) + 1(2) is the same as 2(4+1) right?
anonymous
  • anonymous
yes
anonymous
  • anonymous
but why is it (y-3)(4y+1) now? o.o
amistre64
  • amistre64
well, in this case it aint a 2, its (y-3)
anonymous
  • anonymous
|dw:1328452856397:dw|
anonymous
  • anonymous
= (-y + 4)/(y - 3)
anonymous
  • anonymous
Does it help in any way?
anonymous
  • anonymous
4y = (-y + 4)/(y - 3)
anonymous
  • anonymous
yes it does
anonymous
  • anonymous
thank you guys!
amistre64
  • amistre64
yw
anonymous
  • anonymous
yw

Looking for something else?

Not the answer you are looking for? Search for more explanations.