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anonymous

  • 4 years ago

A rocket is launched from ground level with an initial vertical velocity (v0) of 176 ft/s. After how many seconds will the rocket hit the ground? (Hint: h(t) = -16t2 + v0t + h0). please explain.

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  1. anonymous
    • 4 years ago
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    \[h_0=0\] since the initial heigh of the rocket is 0

  2. anonymous
    • 4 years ago
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    \[v_0=176\] since you are told the initial velocity.

  3. anonymous
    • 4 years ago
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    therefore your equation is \[h(t)=-16t^2+176t\] and you want to know when this is zero, because when it hits the ground the height is 0 feet

  4. anonymous
    • 4 years ago
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    \[-16t^2+176t=0\] \[-16 (t-11) t = 0\] \[t=0,t=11\]

  5. anonymous
    • 4 years ago
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    so eleven seconds it will hit the ground

  6. anonymous
    • 4 years ago
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    thank you for explaining it!

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