anonymous
  • anonymous
A group of 8 boys and 6 girls are to stand in a straight line for a photograph. In how many ways can these 14 children be arranged so that none of the girls stand next to each other?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
\( \large ^9P_6 \times 8! = \cdots \)
anonymous
  • anonymous
@FoolForMath how did you get that?
anonymous
  • anonymous
There are 9 places for 6 girls to go so that no girls would be together.

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More answers

anonymous
  • anonymous
2438553600
anonymous
  • anonymous
but there are only 7 places available so that the girls are not together
anonymous
  • anonymous
_B_B_B_B_B_B_B_B_
anonymous
  • anonymous
two boys could be together too and yet the girls will be separated...
anonymous
  • anonymous
_BB_B_B_B_B_B_B_

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