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anonymous

  • 4 years ago

A group of 8 boys and 6 girls are to stand in a straight line for a photograph. In how many ways can these 14 children be arranged so that none of the girls stand next to each other?

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  1. anonymous
    • 4 years ago
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    \( \large ^9P_6 \times 8! = \cdots \)

  2. anonymous
    • 4 years ago
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    @FoolForMath how did you get that?

  3. anonymous
    • 4 years ago
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    There are 9 places for 6 girls to go so that no girls would be together.

  4. anonymous
    • 4 years ago
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    2438553600

  5. anonymous
    • 4 years ago
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    but there are only 7 places available so that the girls are not together

  6. anonymous
    • 4 years ago
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    _B_B_B_B_B_B_B_B_

  7. anonymous
    • 4 years ago
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    two boys could be together too and yet the girls will be separated...

  8. anonymous
    • 4 years ago
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    _BB_B_B_B_B_B_B_

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spraguer (Moderator)
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